Find the equation of the line with x-intercept 5 and a point on it (-3, 2).

When x-intercept = 5; corresponding point on the x-axis = (5, 0). Slope of the line through (5, 0) and (-3, 2) = . By point-slope form, ⇒ y - y 1 = m(x - x 1 ) ⇒ y - 0 = ⇒ 4y = -1(x - 5) ⇒ 4y = -x + 5 ⇒ x + 4y = 5. Hence, equation of line is x + 4y = 5.