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Mathematics

Find the equation of the line with x-intercept 5 and a point on it (-3, 2).

Straight Line Eq

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Answer

When x-intercept = 5; corresponding point on the x-axis = (5, 0).

Slope of the line through (5, 0) and (-3, 2) = 2035=28=14\dfrac{2 - 0}{-3 - 5} = \dfrac{2}{-8} = -\dfrac{1}{4}.

By point-slope form,

⇒ y - y1 = m(x - x1)

⇒ y - 0 = 14(x5)-\dfrac{1}{4}(x - 5)

⇒ 4y = -1(x - 5)

⇒ 4y = -x + 5

⇒ x + 4y = 5.

Hence, equation of line is x + 4y = 5.

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