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Mathematics

Find the equation of the line whose slope is 56-\dfrac{5}{6} and x-intercept is 6.

Straight Line Eq

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Answer

When x-intercept = 6; corresponding point on the x-axis = (6, 0).

By point-slope form,

⇒ y - y1 = m(x - x1)

⇒ y - 0 = 56(x6)-\dfrac{5}{6}(x - 6)

⇒ 6y = -5(x - 6)

⇒ 6y = -5x + 30

⇒ 5x + 6y = 30.

Hence, equation of line is 5x + 6y = 30.

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