Mathematics
Find the equation of the line with x-intercept 5 and a point on it (-3, 2).
Straight Line Eq
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Answer
When x-intercept = 5; corresponding point on the x-axis = (5, 0).
Slope of the line through (5, 0) and (-3, 2) = .
By point-slope form,
⇒ y - y1 = m(x - x1)
⇒ y - 0 =
⇒ 4y = -1(x - 5)
⇒ 4y = -x + 5
⇒ x + 4y = 5.
Hence, equation of line is x + 4y = 5.
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