Find the slope and y-intercept of the following lines : (i) x - 2y - 1 = 0 (ii) 4x - 5y - 9 = 0 (iii) 3x + 5y + 7 = 0 (iv) (v) y - 3 = 0 (vi) x - 3 = 0

Question

KnowledgeBoat · Accepted Answer

(i) The equation of line is ⇒ x - 2y - 1 = 0 ⇒ 2y = x - 1 ⇒ y = Comparing the above equation with y = mx + c, we get, m = and c = . Hence, the slope of the line = and y-intercept = . (ii) The equation of line is ⇒ 4x - 5y - 9 = 0 ⇒ 5y = 4x - 9 ⇒ y = Comparing the above equation with y = mx + c, we get, m = and c = . Hence, the slope of the line = and y-intercept = . (iii) The equation of line is ⇒ 3x + 5y + 7 = 0 ⇒ 5y = -3x - 7 ⇒ y = Comparing the above equation with y = mx + c, we get, m = and c = . Hence, the slope of the line = and y-intercept = . (iv) The equation of line is Comparing the above equation with y = mx + c, we get, m = and c = 4. Hence, the slope of the line = and y-intercept = 4. (v) The equation of line is ⇒ y - 3 = 0 ⇒ y = 3 ⇒ y = 0.x + 3 Comparing the above equation with y = mx + c, we get, m = 0 and c = 3. Hence, the slope of the line = 0 and y-intercept = 3. (vi) The equation of line is ⇒ x - 3 = 0 ⇒ x = 3. Here, the slope cannot be defined as the line does not meet y-axis. Hence, the slope of the line is undefined and there is no y-intercept as line does not meet y-axis.

Mathematics

Find the slope and y-intercept of the following lines : (i) x - 2y - 1 = 0 (ii) 4x - 5y - 9 = 0 (iii) 3x + 5y + 7 = 0 (iv) (v) y - 3 = 0 (vi) x - 3 = 0

Straight Line Eq

Related Questions

Find the equation of a straight line parallel to y-axis and passing through the point (-3, 5).

The equation of the line PQ is 3y - 3x + 7 = 0.
(i) Write down the slope of the line PQ.
(ii) Calculate the angle that the line PQ makes with the positive direction of x-axis.

Mathematics

Find the slope and y-intercept of the following lines : (i) x - 2y - 1 = 0 (ii) 4x - 5y - 9 = 0 (iii) 3x + 5y + 7 = 0 (iv) (v) y - 3 = 0 (vi) x - 3 = 0

Straight Line Eq

Related Questions

Find the equation of a straight line parallel to y-axis and passing through the point (-3, 5).

The equation of the line PQ is 3y - 3x + 7 = 0.(i) Write down the slope of the line PQ.(ii) Calculate the angle that the line PQ makes with the positive direction of x-axis.

The equation of the line PQ is 3y - 3x + 7 = 0.
(i) Write down the slope of the line PQ.
(ii) Calculate the angle that the line PQ makes with the positive direction of x-axis.