Mathematics
The equation of the line PQ is 3y - 3x + 7 = 0.
(i) Write down the slope of the line PQ.
(ii) Calculate the angle that the line PQ makes with the positive direction of x-axis.
Straight Line Eq
44 Likes
Answer
(i) The equation of line is
⇒ 3y - 3x + 7 = 0
⇒ 3y = 3x - 7
⇒ y =
⇒ y = x - .
Comparing the above equation with y = mx + c, we get,
m = 1.
Hence, the slope of the line PQ is 1.
(ii) We know that m = tan θ
⇒ tan θ = 1
⇒ tan 45° = 1 = tan θ
⇒ θ = 45°
The angle that the line makes with x-axis is 45°.
Answered By
21 Likes
Related Questions
Find the value of p, given that the line passes through the point (-4, 4).
Find the equation of a line whose
(i) slope = 3, y-intercept = -5.
(ii) slope = , y-intercept = 3.
(iii) gradient = , y-intercept =
(iv) inclination = 30°, y-intercept = 2.
Find the slope and y-intercept of the following lines :
(i) x - 2y - 1 = 0
(ii) 4x - 5y - 9 = 0
(iii) 3x + 5y + 7 = 0
(iv)
(v) y - 3 = 0
(vi) x - 3 = 0
The given figure represents the lines y = x + 1 and y = Write down the angles which the lines make with the positive direction of the x-axis. Hence, determine θ.