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Mathematics

The equation of the line PQ is 3y - 3x + 7 = 0.

(i) Write down the slope of the line PQ.

(ii) Calculate the angle that the line PQ makes with the positive direction of x-axis.

Straight Line Eq

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Answer

(i) The equation of line is

⇒ 3y - 3x + 7 = 0

⇒ 3y = 3x - 7

⇒ y = 3x373\dfrac{3\text{x}}{3} - \dfrac{7}{3}

⇒ y = x - 73\dfrac{7}{3}.

Comparing the above equation with y = mx + c, we get,

m = 1.

Hence, the slope of the line PQ is 1.

(ii) We know that m = tan θ

⇒ tan θ = 1
⇒ tan 45° = 1 = tan θ
⇒ θ = 45°

The angle that the line makes with x-axis is 45°.

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