Mathematics
Find the equation of a line whose
(i) slope = 3, y-intercept = -5.
(ii) slope = , y-intercept = 3.
(iii) gradient = , y-intercept =
(iv) inclination = 30°, y-intercept = 2.
Straight Line Eq
27 Likes
Answer
(i) The equation of the straight line is given by,
y = mx + c, where m is the slope and c is the y-intercept.
Given slope = 3 and y-intercept = -5. Putting values in equation we get,
y = 3x - 5.
Hence, the equation of the straight line is y = 3x - 5.
(ii) The equation of straight line is given by,
y = mx + c, where m is the slope and c is the y-intercept.
Given slope = and y-intercept = 3. Putting values in equation we get,
Hence, the equation of straight line is 2x + 7y - 21 = 0.
(iii) The equation of straight line is given by,
y = mx + c, where m is the slope and c is the y-intercept.
Given slope = and y-intercept = . Putting values in equation we get,
Hence, the equation of straight line is
(iv) The equation of straight line is given by,
y = mx + c, where m is the slope and c is the y-intercept.
Given inclination = θ = 30° and y-intercept = 2.
Slope = m = tan θ = tan 30° =
Putting values in equation we get,
Hence, the equation of straight line is
Answered By
17 Likes
Related Questions
The equation of the line PQ is 3y - 3x + 7 = 0.
(i) Write down the slope of the line PQ.
(ii) Calculate the angle that the line PQ makes with the positive direction of x-axis.
Find the slope and y-intercept of the following lines :
(i) x - 2y - 1 = 0
(ii) 4x - 5y - 9 = 0
(iii) 3x + 5y + 7 = 0
(iv)
(v) y - 3 = 0
(vi) x - 3 = 0
Find the equation of a straight line parallel to y-axis and passing through the point (-3, 5).
Find the equation of a straight line parallel to y-axis which is at a distance
(i) 3 units to the right
(ii) 2 units to the left.