Mathematics
Find the equation of a line whose
(i) slope = 3, y-intercept = -5.
(ii) slope = , y-intercept = 3.
(iii) gradient = , y-intercept =
(iv) inclination = 30°, y-intercept = 2.
Straight Line Eq
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Answer
(i) The equation of the straight line is given by,
y = mx + c, where m is the slope and c is the y-intercept.
Given slope = 3 and y-intercept = -5. Putting values in equation we get,
y = 3x - 5.
Hence, the equation of the straight line is y = 3x - 5.
(ii) The equation of straight line is given by,
y = mx + c, where m is the slope and c is the y-intercept.
Given slope = and y-intercept = 3. Putting values in equation we get,
Hence, the equation of straight line is 2x + 7y - 21 = 0.
(iii) The equation of straight line is given by,
y = mx + c, where m is the slope and c is the y-intercept.
Given slope = and y-intercept = . Putting values in equation we get,
Hence, the equation of straight line is
(iv) The equation of straight line is given by,
y = mx + c, where m is the slope and c is the y-intercept.
Given inclination = θ = 30° and y-intercept = 2.
Slope = m = tan θ = tan 30° =
Putting values in equation we get,
Hence, the equation of straight line is
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