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Physics

A body of mass 5 kg falls from a height of 10 m to 4 m.

Calculate:

(i) the loss in potential energy of the body,

(ii) the total energy possessed by the body at any instant? (Take g = 10 ms-2).

Work, Energy & Power

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Answer

Given,

Mass = 5Kg

Fall in height=104Fall in height=6m\text {Fall in height} = 10 - 4 \\[0.5em] \Rightarrow \text {Fall in height} = 6m \\[0.5em]

(i) Loss in potential energy = mg(h1 - h2)

Substituting the vales in formula we get,

Loss in potential energy=5×10×6Loss in potential energy=300J\text{Loss in potential energy} = 5 \times 10 \times 6 \\[0.5em] \Rightarrow \text{Loss in potential energy} = 300J \\[0.5em]

(ii) Total energy remains constant for free fall.

Total energy = P.E + K.E

So, at height 10 m, K.E = 0

Therefore total energy = P.E + K.E

Total energy = mgh + 0

5×10×10=500J5 \times 10 \times 10 = 500J \\[0.5em]

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