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Physics

A hydroelectric power station takes its water from a lake whose water level is 50m above the turbine. Assuming an overall efficiency of 40%, calculate the mass of water which must flow through the turbine each second to produce power output of 1MW. (Take g = 10 m s-2).

Work, Energy & Power

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Answer

Given,

Efficiency = 40%

Work done = 40% of potential energy

Work done=0.4×mgh=0.4×m×10×50=0.4×m×500=200×m\text{Work done} = 0.4 \times mgh \\[0.5em] = 0.4 \times m \times 10 \times 50 \\[0.5em] = 0.4 \times m \times 500 \\[0.5em] = 200 \times m

Power=work donetime1MW=200×mass of water flowing per second1×106=200×mm=1×106200=5000\text{Power} = \dfrac{\text{work done}}{\text{time}} \\[0.5em] 1MW = 200 \times \text {mass of water flowing per second} \\[0.5em] \Rightarrow 1 \times 10^6 = 200 \times m \\[0.5em] \Rightarrow \text m = \dfrac{1 \times 10^6 }{200} \\[0.5em] = 5000

Hence,

Mass of water which must flow through the turbine = 5000Kg

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