Find the value of p, given that the line $\dfrac{y}{2} = x - p$ passes through the point (-4, 4).

Find the equation of a line whose

(i) slope = 3, y-intercept = -5.

(ii) slope = $-\dfrac{2}{7}$, y-intercept = 3.

(iii) gradient = $\sqrt{3}$, y-intercept = $-\dfrac{4}{3}$

(iv) inclination = 30°, y-intercept = 2.

Find the slope and y-intercept of the following lines :

(i) x - 2y - 1 = 0

(ii) 4x - 5y - 9 = 0

(iii) 3x + 5y + 7 = 0

(iv) $\dfrac{x}{3} + \dfrac{y}{4} = 1$

(v) y - 3 = 0

(vi) x - 3 = 0

The given figure represents the lines y = x + 1 and y = $\sqrt{3}x - 1.$ Write down the angles which the lines make with the positive direction of the x-axis. Hence, determine θ.