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Mathematics

Solve for x, 0° ≤ x ≤ 90°

(i) 4 cos2 2x - 3 = 0

(ii) 2 sin2 x - sin x = 0

Trigonometric Identities

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Answer

(i) Given,

⇒ 4 cos2 2x - 3 = 0

⇒ 4 cos2 2x = 3

⇒ cos2 2x = 34\dfrac{3}{4}

⇒ cos 2x = 34\sqrt{\dfrac{3}{4}}

⇒ cos 2x = 32\dfrac{\sqrt{3}}{2}

⇒ cos 2x = cos 30°

⇒ 2x = 30°

⇒ x = 30°2\dfrac{30°}{2} = 15°.

Hence, x = 15°.

(ii) Given,

⇒ 2 sin2 x - sin x = 0

⇒ sin x(2 sin x - 1) = 0

⇒ sin x = 0 or 2 sin x - 1 = 0

⇒ sin x = 0 or 2 sin x = 1

⇒ sin x = 0 or sin x = 12\dfrac{1}{2}

⇒ sin x = sin 0° or sin x = sin 30°

⇒ x = 0° or x = 30°.

Hence, x = 0° or 30°.

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