Mathematics
Solve for x, 0° ≤ x ≤ 90°
(i) 4 cos2 2x - 3 = 0
(ii) 2 sin2 x - sin x = 0
Trigonometric Identities
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Answer
(i) Given,
⇒ 4 cos2 2x - 3 = 0
⇒ 4 cos2 2x = 3
⇒ cos2 2x =
⇒ cos 2x =
⇒ cos 2x =
⇒ cos 2x = cos 30°
⇒ 2x = 30°
⇒ x = = 15°.
Hence, x = 15°.
(ii) Given,
⇒ 2 sin2 x - sin x = 0
⇒ sin x(2 sin x - 1) = 0
⇒ sin x = 0 or 2 sin x - 1 = 0
⇒ sin x = 0 or 2 sin x = 1
⇒ sin x = 0 or sin x =
⇒ sin x = sin 0° or sin x = sin 30°
⇒ x = 0° or x = 30°.
Hence, x = 0° or 30°.
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