S and T are points on sides PR and QR of △ PQR such that ∠P = ∠RTS. Show that △ RPQ ~ △ RTS.
3 Likes
In Δ RPQ and Δ RTS,
⇒ ∠RPQ = ∠RTS (Given)
⇒ ∠PRQ = ∠TRS (Common angle)
∴ Δ RPQ ∼ Δ RTS (By A.A. axiom)
Hence, proved that △ RPQ ~ △ RTS.
Answered By
In the given figure, altitudes AD and CE of ∆ ABC intersect each other at the point P. Show that:
(i) ∆ AEP ~ ∆ CDP
(ii) ∆ ABD ~ ∆ CBE
(iii) ∆ AEP ~ ∆ ADB
(iv) ∆ PDC ~ ∆ BEC
In given figure, if △ ABE ≅ Δ ACD, show that△ ADE ∼ Δ ABC.
