Mathematics
S and T are points on sides PR and QR of △ PQR such that ∠P = ∠RTS. Show that △ RPQ ~ △ RTS.
Triangles
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Answer
In Δ RPQ and Δ RTS,
⇒ ∠RPQ = ∠RTS (Given)
⇒ ∠PRQ = ∠TRS (Common angle)
∴ Δ RPQ ∼ Δ RTS (By A.A. axiom)
Hence, proved that △ RPQ ~ △ RTS.
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