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In the given figure, O is the center of the circle and chord AB : chord CD = 3 : 5. If angle AOB = 60°, angle COD is equal to :

  1. 60°

  2. 120°

  3. 90°

  4. 100°

In the given figure, O is the center of the circle and chord AB : chord CD = 3 : 5. If angle AOB = 60°, angle COD is equal to : Circles, Concise Mathematics Solutions ICSE Class 10.

Circles

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Answer

Given,

Chord AB : Chord CD = 3 : 5

∴ ∠AOB : ∠COD = 3 : 5

⇒ 60° : ∠COD = 3 : 5

⇒ 60°∠COD=35\dfrac{60°}{∠COD} = \dfrac{3}{5}

⇒ ∠COD = 60°×53=300°3\dfrac{60° \times 5}{3} = \dfrac{300°}{3} = 100°.

Hence, Option 4 is the correct option.

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