Mathematics
In the given figure, O is center of the circle, AB || DC and ∠ACD = 32°, ∠DAB is equal to :
122°
148°
90°
none of the above
Related Questions
O' and O" are centers of two circles which intersect each other at points A and B. Then :
BC = BD
BC is larger than BD.
BC is smaller than BD.
C, B and D are collinear.
In the given figure, ∠BAD = 65°, ∠ABD = 70°, ∠BDC = 45°
(i) Prove that AC is a diameter of the circle.
(ii) Find ∠ACB
In the following figure, O is the center of the circle. Find the value of a.
In the given figure, chord AB = chord PB and angle C = 50°. The angle PAB is equal to :
65°
50°
75°
60°
