Mathematics
O' and O" are centers of two circles which intersect each other at points A and B. Then :
BC = BD
BC is larger than BD.
BC is smaller than BD.
C, B and D are collinear.
Circles
3 Likes
Answer
We know that,
Angle in semicircle is a right angle.
From figure,
AC and AD are diameter.
∴ ∠ABC = ∠ABD = 90°.
From figure,
⇒ ∠ABC + ∠ABD = 90° + 90° = 180°.
∴ CBD is a straight line, or points C, B and D are collinear.
Hence, Option 4 is the correct option.
Answered By
2 Likes
Related Questions
In the given figure, O is center of the circle, AB || DC and ∠ACD = 32°, ∠DAB is equal to :
122°
148°
90°
none of the above
In the given figure, chord AB = chord PB and angle C = 50°. The angle PAB is equal to :
65°
50°
75°
60°
In the given figure, O is center of the circle and angle OBA = 50°. The angle P is :
50°
80°
40°
60°
In the given figure, ∠BAD = 65°, ∠ABD = 70°, ∠BDC = 45°
(i) Prove that AC is a diameter of the circle.
(ii) Find ∠ACB
