Mathematics
In the given figure, ABC and AMP are two right triangles, right angled at B and M respectively. Prove that :
(i) Δ ABC ~ Δ AMP
(ii)
Triangles
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Answer
(i) In Δ ABC and Δ AMP,
⇒ ∠ABC = ∠AMP (Both = 90°)
⇒ ∠BAC = ∠MAP (Common angle)
∴ Δ ABC ∼ Δ AMP (By A.A. axiom)
Hence, proved that Δ ABC ~ Δ AMP.
(ii) We know that,
Ratio of corresponding sides in two similar triangles are proportional.
In Δ ABC and Δ AMP,
Hence, proved that .
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