Mathematics
In the following figure, AD and CE are medians of ∆ABC. DF is drawn parallel to CE. Prove that:
(i) EF = FB,
(ii) AG : GD = 2 : 1
![In the figure, AD and CE are medians of ∆ABC. DF is drawn parallel to CE. Prove that: (i) EF = FB, (ii) AG : GD = 2 : 1. Similarity, Concise Mathematics Solutions ICSE Class 10.](https://cdn1.knowledgeboat.com/img/cm10/q13-c15-ex-15-e-similarity-concise-maths-solutions-icse-class-10-992x782.png)
Related Questions
In the figure given below, AB ‖ EF ‖ CD. If AB = 22.5 cm, EP = 7.5 cm, PC = 15 cm and DC = 27 cm.
Calculate: (i) EF (ii) AC
In ΔABC, ∠ABC = ∠DAC, AB = 8 cm, AC = 4 cm and AD = 5 cm.
(i) Prove that ΔACD is similar to ΔBCA.
(ii) Find BC and CD.
(iii) Find the area of ΔACD : area of ΔABC.
The two similar triangles are equal in area. Prove that the triangles are congruent.
The ratio between the altitudes of two similar triangles is 3 : 5; write the ratio between their:
(i) corresponding medians.
(ii) perimeters.
(iii) areas.