Mathematics
In figure given below, AB || DC, BC = AD = 13 cm, AB = 22 cm and DC = 12 cm. Calculate the height of the trapezium ABCD.
Pythagoras Theorem
30 Likes
Answer
From figure,
EF = DC = 12 cm
Since,
AD = BC and DE = CF = h (height)
∴ AE = FB = x.
⇒ AB = AE + EF + FB
⇒ 22 = x + 12 + x
⇒ 2x = 22 - 12
⇒ 2x = 10
⇒ x = 5 cm.
In right triangle ADE,
By pythagoras theorem,
⇒ AD2 = DE2 + AE2
⇒ 132 = h2 + 52
⇒ 169 - 25 = h2
⇒ h2 = 144
⇒ h = 12 cm.
Hence, height = 12 cm.
Answered By
17 Likes
Related Questions
In figure given below, AB || DC, ∠A = 90°, DC = 7 cm, AB = 17 cm and AC = 25 cm. Calculate BC.
In △ABC, AB = AC = x, BC = 10 cm and the area of △ABC is 60 cm2. Find x.
In the figure given below, ABCD is a square of side 7 cm. If
AE = FC = CG = HA = 3 cm,
(i) prove that EFGH is a rectangle.
(ii) find the area and perimeter of EFGH.
In rhombus if diagonals are 30 cm and 40 cm, find its perimeter.