In figure (2) given below, ABCD is an isosceles trapezium. Find the values of x and y.

Sum of adjacent co-interior angles of a trapezium = 180° (As AB || DC)

∴ ∠A + ∠D = 180°

⇒ 2x + 3x = 180°

⇒ 5x = 180°

⇒ x = $\dfrac{180°}{5}$

⇒ x = 36°.

Opposite angles sum of a isosceles trapezium = 180°

∴ ∠A + ∠C = 180°

⇒ 2x + y = 180°

⇒ 2(36°) + y = 180°

⇒ 72° + y = 180°

⇒ y = 108°.

Hence, x = 36° and y = 108°.