Find the equation of the line whose slope is $-\dfrac{5}{6}$ and x-intercept is 6.

When x-intercept = 6; corresponding point on the x-axis = (6, 0).

By point-slope form,

⇒ y - y₁ = m(x - x₁)

⇒ y - 0 = $-\dfrac{5}{6}(x - 6)$

⇒ 6y = -5(x - 6)

⇒ 6y = -5x + 30

⇒ 5x + 6y = 30.

Hence, equation of line is 5x + 6y = 30.