Mathematics
Describe the locus of vertices of all isosceles triangles having a common base.
Locus
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Answer
We know that,
The locus of point equidistant from two points is the perpendicular bisector of the line joining those points.
Steps of construction :
Draw a line segment BC (common base)
Draw XY, perpendicular bisector of BC.
Mark point P on XY.
So, PB = PC as P lies on perpendicular bisector of BC.
Hence, the locus of vertices of all isosceles triangles having a common base will be the perpendicular bisector of the common base of the triangles.
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