ABCD is a square, F is mid-point of AB and BE is one third of BC. If area of △FBE is 108 cm 2 , find the length of AC.

Let x cm be the side of each square. Since, F is midpoint of AB so, FB = cm BE is one third of BC, BE = . Given, area of △FBE is 108 cm 2 Length of diagonal of square = Side = cm. Hence, length of diagonal of square = cm.

In a quadrilateral ABCD, ∠B = 90°. If AD² = AB² + BC² + CD², Prove that ∠ACD = 90°.

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In the adjoining figure, find the length of AD in terms of b and c.

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In the adjoining figure, △PQR is right angled at Q and points S and T trisect side QR. Prove that
8PT² = 3PR² + 5PS².

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In a triangle ABC, AB = AC and D is a point on side AC such that BC² = AC × CD.
Prove that BD = BC.

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Mathematics

ABCD is a square, F is mid-point of AB and BE is one third of BC. If area of △FBE is 108 cm², find the length of AC.

Pythagoras Theorem

Related Questions

In a quadrilateral ABCD, ∠B = 90°. If AD² = AB² + BC² + CD², Prove that ∠ACD = 90°.

In the adjoining figure, find the length of AD in terms of b and c.

In the adjoining figure, △PQR is right angled at Q and points S and T trisect side QR. Prove that
8PT² = 3PR² + 5PS².

In a triangle ABC, AB = AC and D is a point on side AC such that BC² = AC × CD.
Prove that BD = BC.

Mathematics

ABCD is a square, F is mid-point of AB and BE is one third of BC. If area of △FBE is 108 cm2, find the length of AC.

Pythagoras Theorem

Related Questions

In a quadrilateral ABCD, ∠B = 90°. If AD2 = AB2 + BC2 + CD2, Prove that ∠ACD = 90°.

In the adjoining figure, find the length of AD in terms of b and c.

In the adjoining figure, △PQR is right angled at Q and points S and T trisect side QR. Prove that8PT2 = 3PR2 + 5PS2.

In a triangle ABC, AB = AC and D is a point on side AC such that BC2 = AC × CD.Prove that BD = BC.

ABCD is a square, F is mid-point of AB and BE is one third of BC. If area of △FBE is 108 cm², find the length of AC.

In a quadrilateral ABCD, ∠B = 90°. If AD² = AB² + BC² + CD², Prove that ∠ACD = 90°.

In the adjoining figure, △PQR is right angled at Q and points S and T trisect side QR. Prove that
8PT² = 3PR² + 5PS².

In a triangle ABC, AB = AC and D is a point on side AC such that BC² = AC × CD.
Prove that BD = BC.