Mathematics
ABCD is a cyclic quadrilateral such that AB is a diameter of the circle circumscribing it and ∠ADC = 140°, then ∠BAC is equal to
80°
50°
40°
30°
Answer
Cyclic quadrilateral ABCD is shown in the figure below:
The sum of opposite angles in a quadrilateral = 180°.
∴ ∠ADC + ∠ABC = 180°
140° + ∠ABC = 180°
∠ABC = 180° - 140° = 40°.
In △ABC,
∠ACB = 90° (∵ angles in semicircle = 90°.)
Since, sum of angles in a triangle = 180°.
In △ABC,
⇒ ∠ABC + ∠ACB + ∠BAC = 180°
⇒ 40° + 90° + ∠BAC = 180°
⇒ 130° + ∠BAC = 180°
⇒ ∠BAC = 180° - 130°
⇒ ∠BAC = 50°.
Hence, Option 2 is the correct option.
Related Questions
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60°
45°
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In the adjoining figure, O is the centre of the circle. If ∠BAO = 60°, then ∠ADC is equal to
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In the adjoining figure, O is the centre of the circle. If ∠OAB = 40°, then ∠ACB is equal to
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In the adjoining figure, if O is the centre of the circle then the value of x is
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