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ABCD is a cyclic quadrilateral such that AB is a diameter of the circle circumscribing it and ∠ADC = 140°, then ∠BAC is equal to

  1. 80°

  2. 50°

  3. 40°

  4. 30°

Circles

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Answer

Cyclic quadrilateral ABCD is shown in the figure below:

In the adjoining figure, O is the centre of the circle. If ∠OAB = 40°, then ∠ACB is equal to (a) 80° (b) 50° (c) 40° (d) 30°. Circles, ML Aggarwal Understanding Mathematics Solutions ICSE Class 10.

The sum of opposite angles in a quadrilateral = 180°.

∴ ∠ADC + ∠ABC = 180°

140° + ∠ABC = 180°
∠ABC = 180° - 140° = 40°.

In △ABC,

∠ACB = 90° (∵ angles in semicircle = 90°.)

Since, sum of angles in a triangle = 180°.

In △ABC,

⇒ ∠ABC + ∠ACB + ∠BAC = 180°
⇒ 40° + 90° + ∠BAC = 180°
⇒ 130° + ∠BAC = 180°
⇒ ∠BAC = 180° - 130°
⇒ ∠BAC = 50°.

Hence, Option 2 is the correct option.

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