Equations Worksheet
Question 1
Hydrogen Chloride | Complete and balance the equations |
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a. Preparation of hydrogen chloride | |
1. By direct combination | H2 + Cl2 ⟶ ............... |
2. Laboratory preparations [metal chloride] | |
Answer
Hydrogen Chloride | Complete and balance the equations |
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a. Preparation of hydrogen chloride | |
1. By direct combination | H2 + Cl2 ⟶ 2HCl |
2. Laboratory preparations [metal chloride] | |
Question 2
b. Properties of hydrogen chloride | |
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3. Thermal dissociation | |
4. Reaction with ammonia | NH3 + HCl ⟶ ............... |
Hydrocloric acid [dilute] | |
5. Monobasic acid | ; [H+ + H2O ⟶ ...............] |
Reaction with | |
6. Active metal | Al + HCl ⟶ ............... + ............... |
7. Base - copper [II] oxide - ammonium hydroxide | CuO + HCl ⟶ ............... + ............... NH4OH + HCl ⟶ ............... + ............... |
8. Sodium carbonate | Na2CO3 + HCl ⟶ ............... + H2O + ............... |
9. Sodium hydrogen carbonate | NaHCO3 + HCl ⟶ ............... + H2O + ............... |
10. Sodium sulphite | Na2SO3 + HCl ⟶ ............... + H2O + ............... |
11. Sodium bisulphite | NaHSO3 + HCl ⟶ ............... + H2O + ............... |
12. Iron [II] sulphide | FeS + HCl ⟶ ............... + ............... |
13. Silver nitrate | AgNO3 + HCl ⟶ ............... + ............... |
14. Lead nitrate | Pb(NO3)2 + HCl ⟶ ............... + ............... |
15. Sodium thiosulphate soln. | Na2S2O3 + HCl ⟶ ............... + ............... + ............... + ............... |
Oxidising agents | |
16. Lead dioxide [lead [IV] oxide] | PbO2 + HCl ⟶ ............... + H2O + ............... |
17. Red lead [trilead tetroxide] | Pb3O4 + HCl ⟶ ............... + H2O + ............... |
18. Potassium permanganate | KMnO4 + ............... ⟶ ............... + ............... + ............... + Cl2 |
19. Potassium dichromate | |
20. Nitric acid [conc.] | HNO3 + 3HCl ⟶ ............... + ............... + Cl2 [Au + [Cl] ⟶ ............... ] |
Answer
b. Properties of hydrogen chloride | |
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3. Thermal dissociation | |
4. Reaction with ammonia | NH3 + HCl ⟶ NH4Cl |
Hydrocloric acid [dilute] | |
5. Monobasic acid | ; [H+ + H2O ⟶ H3O+ ] |
Reaction with | |
6. Active metal | 2Al + 6HCl ⟶ 2AlCl3 + 3H2 |
7. Base - copper [II] oxide - ammonium hydroxide | CuO + 2HCl ⟶ CuCl2 + H2O NH4OH + HCl ⟶ NH4Cl + H2O |
8. Sodium carbonate | Na2CO3 + 2HCl ⟶2NaCl + H2O + CO2 |
9. Sodium hydrogen carbonate | NaHCO3 + HCl ⟶ NaCl + H2O + CO2 |
10. Sodium sulphite | Na2SO3 + 2HCl ⟶ 2NaCl + H2O + SO2 |
11. Sodium bisulphite | NaHSO3 + HCl ⟶ NaCl + H2O + SO2 |
12. Iron [II] sulphide | FeS + 2HCl ⟶ FeCl2 + H2S |
13. Silver nitrate | AgNO3 + HCl ⟶ AgCl + HNO3 |
14. Lead nitrate | Pb(NO3)2 + 2HCl ⟶ PbCl2 + 2HNO3 |
15. Sodium thiosulphate soln. | Na2S2O3 + 2HCl ⟶ 2NaCl + SO2 + S + H2O |
Oxidising agents | |
16. Lead dioxide [lead [IV] oxide] | PbO2 + 4HCl ⟶ PbCl2 + 2H2O + Cl2 |
17. Red lead [trilead teroxide] | Pb3O4 + 8HCl ⟶ 3PbCl2 + 4H2O + Cl2 |
18. Pottasium permaganate | 2KMnO4 + 16HCl ⟶ 2KCl + 2MnCl2 + 8H2O + 5Cl2 |
19. Pottasium dichromate | |
20. Nitric acid [conc.] | HNO3 + 3HCl ⟶ NOCl + 2H2O + 2[Cl] [Au + 3[Cl] ⟶ AuCl3 ] |
Question 3
Tests for hydrochloric acid | |
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21. Glass rod dipped in ammonia soln. | NH3 + ............... ⟶ ............... |
22. Addition of silver nitrate soln. | AgNO3 + ............... ⟶ ............... ↓ + ............... |
23. Solubility of silver chloride | AgCl + NH4OH ⟶ ............... + ............... |
24. Heated with manganese dioxide [manganese [IV] oxide] | ............... + HCl ⟶ MnCl2 + ............... + ............... [g] |
Answer
Tests for hydrochloric acid | |
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21. Glass rod dipped in ammonia soln. | NH3 + HCl ⟶ NH4Cl |
22. Addition of silver nitrate soln. | AgNO3 + HCl ⟶ AgCl ↓ + HNO3 |
23. Solubility of silver chloride | AgCl + 2NH4OH ⟶ [Ag(NH3)2Cl)] + 2H2O |
24. Heated with manganese dioxide [manganese [IV] oxide] | MnO2 + 4HCl ⟶ MnCl2 + 2H2O + Cl2 [g] |
Questions
Question 1(2007)
Write a balanced equation for Sodium chloride from sodium carbonate soln. and dilute hydrochloric acid.
Answer
Na2CO3 + 2HCl [dil.] ⟶ 2NaCl + H2O + CO2 [g.]
Question 2(2007)
Of the two gases, NH3 and HCl, which is more dense. Name the method of collection of this gas.
Answer
Hydrogen chloride gas is denser than NH3.
Reason — V.D. of NH3 = 8.5 and that of HCl = 18.25
HCl gas is collected by upward displacement of air.
Question 3(2007)
Give one example of a reaction between the above two gases which produces a solid.
Answer
NH3 [g] + HCl [g] ⟶ NH4Cl (s-solid)
When a gas jar containing HCl gas in inverted over a jar full of ammonia gas, dense white fumes are formed. These fumes consist of particles of solid ammonium chloride suspended in air.
Question 4(2007)
Write equations for the reaction of dil. HCl with each of the following :
(i) iron
(ii) sodium hydrogen carbonate
(iii) iron [II] sulphide
(iv) sodium sulphite
Answer
(i) Fe + 2HCl ⟶ FeCl2 + H2
(ii) NaHCO3 + HCl ⟶ NaCl + H2O + CO2
(iii) FeS + 2HCl ⟶ FeCl2 + H2S
(iv) Na2SO3 + 2HCl ⟶ 2NaCl + H2O + SO2 [g]
Question 1(2008)
What property of hydrogen chloride is demonstrated when it is collected by downward delivery [upward displacement]. Why is hydrogen chloride not collected over water.
Answer
Hydrogen chloride is 1.28 times heavier than air, hence it is collected by downward delivery [upward displacement]. Hydrogen chloride is not collected over water since it is highly soluble in water.
Question 2(2008)
Write equations for the reactions :
(i) dil. HCl and sodium thiosulphate.
(ii) dil. HCl and lead nitrate soln.
Answer
(i) Na2S2O3 + 2HCl ⟶ 2NaCl + SO2 + S + H2O
(ii) Pb(NO3)2 + 2HCl ⟶ PbCl2 ↓ + 2HNO3
Question 1(2009)
Name the gas evolved - The gas produced by the action of concentrated sulphuric acid on sodium chloride.
Answer
Hydrogen chloride (HCl)
Question 2(2009)
Match each substance A to E listed below with the appropriate description given below :
[A] Sulphur
[B] Silver chloride
[C] Hydrogen chloride
[D] Copper [II] Sulphate
[E] Graphite.
(i) A covalent compound which behaves like an ionic compound in aqueous solution.
(ii) A compound which is insoluble in cold water but soluble in excess of ammonia solution.
Answer
(i) [C] Hydrogen chloride
(ii) [B] Silver chloride
Question 3(2009)
Write a balanced equation for each of the following :
(i) Red lead is warmed with concentrated hydrochloric acid.
(ii) Magnesium metal is treated with dilute hydrochloric acid.
Answer
(i)
(ii) Mg + 2HCl ⟶ MgCl2 + H2
Question 4(2009)
Correct the statement:
HCl acid is prepared in the lab. by passing hydrogen chloride directly through water.
Answer
HCl acid is prepared in the lab. by passing hydrogen chloride gas in water using a special funnel arrangement.
Question 1(2010)
Select the correct answer from A, B, C and D.
(i) Aqua regia is a mixture of :
A : Dilute hydrochloric and conc. nitric acid
B : Conc. hydrochloric and dilute nitric acid
C : One part of conc. hydrochloric acid and 3 parts of conc. nitric acid.
D : 3 parts of conc. hydrochloric acid and 1 part of conc. nitric acid
Answer
D : 3 parts of conc. hydrochloric acid and 1 part of conc. nitric acid
Question 2(2010)
State your observation when :
A glass rod dipped in NH4OH soln. is brought near an open bottle containing conc. HCl
Answer
Dense white fumes of ammonium chloride are formed when a glass rod dipped in NH4OH soln. is brought near an open bottle containing conc. HCl
Question 3(2010)
(i) State the salt and the acid, used in the laboratory preparation of hydrogen chloride.
(ii) Give the equation for the preparation.
(iii) State a method to prove that the gas jar used for collection of HCl gas is filled with hydrogen chloride.
(iv) Observing the method of collection of the gas, state what you can tell about the density of hydrogen chloride.
Answer
(i) Salt — Sodium Chloride [NaCl], Acid — Sulphuric acid [H2SO4]
(ii)
(iii) A glass rod dipped in NH4OH soln. is brought near the mouth of the gas jar 'Y'. If the gas jar is full with HCl gas then dense white fumes of ammonium chloride are formed.
(iv) This method indicates that HCl gas is heavier than air.
Question 4(2010)
How would you distinguish between dilute HCl and dilute HNO3, by addition of only one solution.
Answer
When silver nitrate soln. is added to dil. HCl, curdy white ppt. of silver chloride is formed. Whereas, there is no reaction when silver nitrate soln. is added to dil. HNO3.
AgNO3 + HCl ⟶ AgCl (white ppt.) + HNO3
AgNO3 + HNO3 ⟶ no reaction
Question 5(2010)
Name two gases which can be used in the study of the fountain experiment. State the common property demonstrated by the fountain experiment ?
Answer
Dry hydrogen chloride gas (HCl) and Ammonia (NH3) gas can be used in the study of the fountain experiment.
High solubility of HCl gas in water is the common property demonstrated by the fountain experiment.
Question 1(2011)
Choose the correct answer:
Hydrogen chloride gas being highly soluble in water is dried by :
- Anhydrous calcium chloride
- Phosphorous pentaoxide
- Quick lime
- Conc. sulphuric acid.
Answer
Concentrated sulphuric acid.
Reason — Drying agent used for drying should only remove the moisture and not react with it, hence, conc. sulphuric acid is used as the drying agent.
Question 2(2011)
Write balanced equation of dil. HCl with Calcium bicarbonate.
Answer
Ca(HCO3)2 + 2HCl ⟶ CaCl2 + 2H2O + 2CO2
Question 3(2011)
In the laboratory preparation of hydrochloric acid, hydrogen chloride gas is dissolved in water.
(i) Draw a diagram to show the arrangement used for the absorption of HCl gas in water.
(ii) State why such an arrangement is necessary? Give two reasons for the same.
(iii) Write balanced chemical equations for the laboratory preparation of HCl gas when the reactants are :
(A) below 200°C
(B) above 200°C
Answer
(i) Below diagrams show the special funnel arrangement used for the absorption of HCl gas in water:
(ii) The reasons are :
- Prevents or minimizes back-suction of water.
- Provides a large surface area for the absorption of the HCl gas.
(iii) The equations are:
(A)
(B)
Question 1(2012)
Rewrite the correct statement with the missing word/s : Aqua regia contains one part by volume of nitric acid and three parts by volume of hydrochloric acid.
Answer
Aqua regia contains one part by volume of conc. nitric acid and three parts by volume of conc. hydrochloric acid.
Question 2(2012)
Give reason for the following : Hydrogen chloride gas cannot be dried over quick lime.
Answer
Quicklime [CaO] is alkaline in nature and it reacts with HCl forming the respective chloride. Hence, it can't be used as a drying agent.
Question 3(2012)
Give a balanced equation for the reaction : Conc. hydrochloric acid and potassium permanganate solution.
Answer
Question 4(2012)
Give balanced equations with conditions, if any, for the following conversions A to D.
A : Sodium Chloride ⟶ Hydrogen Chloride
B : Hydrogen Chloride ⟶ Iron (II) chloride
C : Hydrogen Chloride ⟶ Ammonium chloride
D : Hydrogen Chloride ⟶ Lead chloride.
Answer
A:
B: Fe + 2HCl (dil.) ⟶ FeCl2 + H2 [g]
C: NH4OH + HCl (dil.)⟶ NH4Cl + H2O
D:
Question 1(2013)
Identify the gas evolved when :
(i) Potassium sulphite is treated with dilute hydrochloric acid.
(ii) Concentrated hydrochloric acid is made to react with manganese dioxide.
Answer
(i) Sulphur dioxide gas
(ii) Chlorine gas
Question 2(2013)
State one appropriate observation for :
(i) Copper sulphide is treated with dilute hydrochloric acid.
(ii) A few drops of dil. HCl are added to AgNO3 soln. followed by addition of NH4OH soln.
Answer
(i) A colourless gas having smell of rotten eggs is given off. The gas evolved is H2S
CuS + 2HCl ⟶ CuCl2 + H2S
(ii) Curdy white precipitate of silver chloride [AgCl] is obtained, which is soluble in excess of NH4OH.
AgNO3 + HCl ⟶ AgCl ↓ + HNO3
AgCl + 2NH4OH ⟶ [Ag(NH3)2Cl)] + 2H2O
Question 1(2014)
Fill in the blank from the choices in the bracket :
Quicklime is not used to dry HCl gas because ............... [CaO is alkaline, CaO is acidic, CaO is neutral]
Answer
Quicklime is not used to dry HCl gas because CaO is alkaline.
Question 2(2014)
Write the balanced equation for:
Action of dilute hydrochloric acid on sodium sulphide.
Answer
Action of dilute hydrochloric acid on sodium sulphide.
Na2S + 2HCl ⟶ 2NaCl + H2S [g.]
Question 3(2014)
State your observation:
Dilute HCl is added to sodium carbonate crystals.
Answer
Na2CO3 + 2HCl ⟶ 2NaCl + H2O + CO2 ↑
Effervescence of CO2 seen which turns lime water milky
Question 4(2014)
Study the figure given below and answer the questions that follow :
(i) Identify the gas Y.
(ii) What property of gas Y does this experiment demonstrate?
(iii) Name another gas which has the same property and can be demonstrated through this experiment.
Answer
(i) Dry HCl (Hydrogen chloride) gas is the gas Y
(ii) High solubility of HCl in water
(iii) Ammonia (NH3) gas also demonstrates high solubility in water.
Question 1(2015)
Select from the gases — ammonia, ethane, hydrogen chloride, hydrogen sulphide, ethyne — The gas which produces dense white fumes with ammonia gas.
Answer
Hydrogen chloride
NH3 [g] + HCl [g] ⟶ NH4Cl (s-solid)
When a gas jar containing HCl gas in inverted over a jar full of ammonia gas, dense white fumes are formed. These fumes consists of particles of solid ammonium chloride suspended in air.
Question 2(2015)
Identify the acid which on mixing with AgNO3 soln. gives a white precipitate, soluble in excess ammonium hydroxide.
Answer
Dilute hydrochloric acid
AgNO3 + HCl ⟶ AgCl (white ppt.) + HNO3
Question 3(2015)
The following questions pertain to the laboratory preparation of hydrogen chloride gas:
(i) Write the equation for it's preparation mentioning the condition required.
(ii) Name the drying agent used in the above preparation and give a reason for the choice.
(iii) State a safety precaution taken during the preparation of hydrochloric acid.
Answer
(i) The equation for the laboratory preparation of hydrogen chloride gas :
(ii) Concentrated sulphuric acid is used as the drying agent used in the above preparation.
Reason — Drying agent used for drying should only remove the moisture and not react with it, hence, conc. sulphuric acid is used as the drying agent.
(iii) The precautions taken are:
- The reaction mixture is initially heated very slowly to control the evolution of HCl gas.
- The lower end of the thistle funnel should dip below the acid in the flask otherwise the HCl gas obtained will escape out from the thistle funnel.
Question 1(2016)
Select the correct answer from A, B, C and D : The aim of the Fountain experiment is to prove that :
(A) HCl turns blue litmus red
(B) HCl is denser than air
(C) HCl is highly soluble in water
(D) HCl fumes in moist air.
Answer
(C) HCl is highly soluble in water
Question 2(2016)
Fill in the blank : ...............[AgCl / PbCl2], a white precipitate is soluble in excess NH4OH.
Answer
AgCl, a white precipitate is soluble in excess NH4OH.
Question 3(2016)
Write balanced chemical equation for : Action of hydrochloric acid on sodium bicarbonate.
Answer
NaHCO3 + HCl ⟶ NaCl + H2O + CO2 ↑
Question 4(2016)
State your observations when dilute hydrochloric acid is added to :
(i) Lead nitrate soln. and the mixture is heated.
(ii) Copper carbonate.
(iii) Sodium thiosulphate.
Answer
(i) White precipitate of PbCl2 is formed which is soluble in hot water.
Pb(NO3)2 + 2HCl ⟶ PbCl2 ↓ + 2HNO3
(ii) Effervescence of CO2 seen which turns lime water milky
CuCO3 + 2HCl ⟶ CuCl2 + H2O + CO2
(iii) Yellow particles of S precipitate.
Na2S2O3 + 2HCl ⟶ 2NaCl + SO2 + S + H2O
Question 5(2016)
Identify the gas evolved and give the chemical test when dilute hydrochloric acid reacts with :
(i) Sodium sulphite.
(ii) Iron [II] sulphide.
Answer
(i) SO2 is evolved when dilute hydrochloric acid reacts with sodium sulphite.
Na2SO3 + 2HCl ⟶ 2NaCl + H2O + SO2 [g]
(ii) H2S gas is evolved when dilute hydrochloric acid reacts with Iron [II] sulphide.
FeS + 2HCl ⟶ FeCl2 + H2S
Question 1(2017)
Fill in the blanks –
Potassium sulphite on reacting with hydrochloric acid, releases ............... gas. [Cl2, SO2, H2S]
Answer
Potassium sulphite on reacting with hydrochloric acid, releases SO2 gas.
Question 2(2017)
Identify the substance underlined – A solid formed by the reaction of two gases, one of which is acidic and the other basic in nature.
Answer
Ammonium chloride.
NH3 [g] + HCl [g] ⟶ NH4Cl (s-solid)
Question 3(2017)
State one relevant observation – Action of dilute hydrochloric acid on iron [II] sulphide.
Answer
H2S gas is evolved. It has a foul smell like rotten eggs.
FeS + 2HCl [g] ⟶ FeCl2 + H2S
Question 4(2017)
Certain blanks spaces are left in the following table as A & B. Identify each of them.
Lab preparation of | Reactants used | Products formed | Drying agent | Method of collection |
---|---|---|---|---|
HCl gas | NaCl + H2SO4 | A | Conc. H2SO4 | B |
Answer
A : The products are sodium hydrogen sulphate (NaHSO4) and HCl gas.
B : HCl gas is collected by the upward displacement of air method.
Question 1(2018)
Write a balanced chemical equation for - Action of dilute hydrochloric acid on magnesium sulphite.
Answer
MgSO3 + 2HCl ⟶ MgCl2 + H2O + SO2 [g]
Question 2(2018)
State one relevant observation - Lead nitrate solution is mixed with dilute hydrochloric acid and heated.
Answer
White precipitate of PbCl2 is formed which is soluble in hot water.
Pb(NO3)2 + 2HCl ⟶ PbCl2 + 2HNO3
Question 3(2018)
Name the gas that is produced during - Action of dilute hydrochloric acid on sodium sulphide.
Answer
H2S gas is evolved.
Na2S + 2HCl ⟶ 2NaCl + H2S [g.]
Question 4(2018)
Fill in the blank with the correct choice given in the bracket - Dry hydrogen chloride gas can be collected by ............... displacement of air. [downward/upward]
Answer
Dry hydrogen chloride gas can be collected by upward displacement of air.
Question 5(2018)
Name the acid used for the preparation of - hydrogen chloride gas in the laboratory. State why this particular acid is preferred to other acids.
Answer
Conc. H2SO4 is used for the preparation of hydrogen chloride gas in the laboratory.
As conc. H2SO4 is non-volatile and has a high boiling point, therefore, it displaces the volatile hydrogen chloride from the salt sodium chloride. Hence, conc. H2SO4 is used as a reactant in the laboratory preparation of HCl from sodium chloride
Question 6(2018)
Write a balanced chemical equation for - The laboratory preparation of hydrogen chloride gas.
Answer
Question 7(2018)
For the preparation of hydrochloric acid in the laboratory —
(i) State why direct absorption of hydrogen chloride gas in water is not feasible.
(ii) State what arrangement is used to dissolve hydrogen chloride gas in water.
Answer
(i) Direct absorption of hydrogen chloride gas in water is not feasible because it causes back suction in the delivery tube.
- Hydrogen chloride gas is extremely soluble in water.
- If a delivery tube through which HCl gas is passed is directly immersed in water, the rate of absorption of HCl gas is high and hence a partial vacuum is created in the tube.
- The pressure outside being higher causes the water to be pushed up into the delivery tube and damages the apparatus. This is called back-suction.
(ii) Special funnel arrangement is used for avoiding back suction. It (a) Prevents or minimizes back-suction of water (b) Provides a large surface area for absorption of HCl gas.
- The rim of the funnel is placed so that it just touches the trough containing water. If back-suction occurs, the water rises up the funnel and the level outside the funnel falls, creating an air gap between the rim of the funnel and the surface of water.
- The pressure outside and inside equalize and the water which had risen in the funnel falls down again. This process continues till the water in the trough is saturated with hydrogen chloride gas resulting in the formation of hydrochloric acid.
- Hence, hydrochloric acid is not prepared in the laboratory by passing hydrogen chloride gas directly through water, but prepared using a special funnel arrangement.
Question 1(2019)
Choose the correct answer from the options A, B, C and D given :
The drying agent used to dry HCl gas is :
A : Conc. H2SO4
B : ZnO
C : Al2O3
D : CaO
Answer
Conc. H2SO4
Reason — Drying agent used for drying should only remove the moisture and not react with it, hence, conc. sulphuric acid is used as the drying agent.
Question 2(2019)
Fill in the blanks with the choices given in the bracket:
When sodium chloride is heated with concentrated sulphuric acid below 200°C, one of the products formed is ............... [sodium hydrogen sulphate / sodium sulphate / chlorine]
Answer
When sodium chloride is heated with concentrated sulphuric acid below 200°C, one of the products formed is sodium hydrogen sulphate
Question 3(2019)
State one observation for the following:
A small piece of zinc is added to dilute hydrochloric acid.
Answer
Effervescence of H2 gas can be seen.
Zn + 2HCl ⟶ ZnCl2 + H2
Question 1(2020)
State one relevant reason for:
Hydrogen chloride gas fumes in moist air.
Answer
Due to its high solubility, HCl gas fumes in moist air and forms a mist of droplets of HCl acid.
Question 2(2020)
Complete the following by selecting the correct option from the choices given.
(i) The indicator which does not change colour on passage of HCl gas is .............. [methyl orange, moist blue litmus, phenolphthalein].
(ii) The acid which cannot act as an oxidizing agent is ............... [conc. H2SO4, conc. HNO3, conc. HCl]
Answer
(i) The indicator which does not change colour on passage of HCl gas is phenolphthalein.
(ii) The acid which cannot act as an oxidizing agent is conc. HCl
Question 3(2020)
Hydrogen chloride gas is prepared in the laboratory using conc. H2SO4 and NaCl. Answer the questions that follow based on this reaction.
(i) Give the balanced chemical equation for the reaction with suitable condition[s] if any.
(ii) Why is concentrated sulphuric acid used instead of conc. nitric acid.
(iii) How is the gas collected.
(iv) Name the drying agent not used for drying the gas.
Answer
(i) Balanced chemical equation for the reaction are :
(ii) As conc. H2SO4 is non-volatile and has a high boiling point, therefore, it displaces the volatile hydrogen chloride from the salt sodium chloride. Hence, conc. H2SO4 is used as a reactant in the laboratory preparation of HCl from sodium chloride.
Conc. nitric acid cannot be used in place of conc. H2SO4 since it is volatile and may volatize out along with the hydrogen chloride.
(iii) The gas is collected by upward displacement of air method.
(iv) Quicklime (CaO) and phosphorous pentoxide [P2O5] are not used as drying agent, since they react with HCl forming their respective chlorides.
Complete the Statements
Question 1
Complete the statements given below pertaining to hydrogen chloride gas or hydrochloric acid:
- Hydrogen chloride gas is not dried using ............... [conc.H2SO4, CaO].
- Hydrogen chloride gas on heating above 500°C gives hydrogen and chlorine. The reaction is an example of ............... [thermal decomposition, thermal dissociation].
- Iron reacts with hydrogen chloride gas forming ............. [iron (II) chloride, iron (III) chloride] and hydrogen. The reaction is an example of ............... [double decomposition, synthesis, simple displacement].
- Hydrogen chloride and water are examples of ............... [polar covalent compounds, non-polar covalent compounds] and a solution of hydrogen chloride in water ............... [contains, does not contain] free ions.
- Addition of ............... [sodium nitrate, zinc nitrate, silver nitrate] to hydrochloric acid, gives an insoluble precipitate of the respective chloride. This precipitate is ............... [soluble, insoluble] in ammonium hydroxide and ............... [soluble, insoluble] in dilute nitric acid.
- Addition of ............... [iron (III) sulphide, iron (II) sulphide, iron pyrites] to dilute hydrochloric acid results in liberation of hydrogen sulphide gas.
- Aqua regia is a mixture of ............... [one, two, three] part/s of concentrated nitric acid and ............... [one, two, three] part/s of concentrated hydrochloric acid by .............. [weight, volume]. In aqua regia, nitric acid ............... [oxidises, reduces] hydrochloric acid to chlorine.
- Hydrochloric acid can be converted into chlorine by heating with ............... [calcium oxide, lead (II) oxide, lead (IV) oxide] which acts as a/an ............... [oxidising, reducing] agent.
Answer
- Hydrogen chloride gas is not dried using CaO.
- Hydrogen chloride gas on heating above 500°C gives hydrogen and chlorine.The reaction is an example of thermal dissociation.
- Iron reacts with hydrogen chloride gas forming iron (II) chloride and hydrogen. The reaction is an example of simple displacement.
- Hydrogen chloride and water are examples of polar covalent compounds and a solution of hydrogen chloride in water contains free ions.
- Addition of silver nitrate to hydrochloric acid, gives an insoluble precipitate of the respective chloride. This precipitate is soluble in ammonium hydroxide and insoluble in dilute nitric acid.
- Addition of iron (II) sulphide to dilute hydrochloric acid results in liberation of hydrogen sulphide gas.
- Aqua regia is a mixture of one part/s of concentrated nitric acid and three part/s of concentrated hydrochloric acid by volume. In aqua regia, nitric acid oxidises hydrochloric acid to chlorine.
- Hydrochloric acid can be converted into chlorine by heating with lead (IV) oxide which acts as an oxidising agent.
Additional Questions
Question 1
Give a reason why:
(a) gastric juices of mammals are acidic
(b) HCl is considered a polar covalent compound.
Answer
(a) HCl is present in gastric juices of mammals, hence the gastric juices of mammals are acidic. It helps in digestion.
(b) Due to difference in electronegativities of H and Cl the bond in HCl is polar covalent.
Question 2
Give the equation for preparation of HCl gas by synthesis. State two conditions involved in the synthesis.
Answer
Moist hydrogen gas combines with chlorine in the presence of diffused sunlight.
- The reaction is explosive in direct sunlight and negligible in the dark. Moisture acts as a catalyst in the above synthesis reaction.
- Burning jet of hydrogen also burns in chlorine forming hydrogen chloride.
Question 3
Give a balanced equation for preparation of HCl gas in the laboratory from sodium chloride.
Answer
Below is the balanced equation for preparation of HCl gas in the laboratory from sodium chloride:
Question 4
In the laboratory preparation of HCl from sodium chloride, state why the following are preferred –
(i) Conc. H2SO4 as a reactant
(ii) Temp. below 200°C
(iii) Conc. H2SO4 as a drying agent.
Answer
(i) As conc. H2SO4 is non-volatile and has a high boiling point, therefore, it displaces the volatile hydrogen chloride from the salt sodium chloride. Hence, conc. H2SO4 is used as a reactant in the laboratory preparation of HCl from sodium chloride
(ii) The fuel is not wasted, the glass apparatus does not crack and sodium sulphate does not form hard crust, which in turn may stick to the glass and will be difficult to remove. Therefore, temperature below 200°C is used.
(iii) Drying agent used for drying should only remove the moisture and not react with it, hence, conc. sulphuric acid is used as the drying agent.
Question 5
State with reasons the method of collection of HCl gas in the laboratory.
Answer
Dry HCl gas is collected by the upward displacement of air because it is 1.28 times heavier than air. It is highly soluble in water, hence not collected over water.
Question 6
Compare the density of HCl gas with air and state the solubility of HCl gas in water.
Answer
V.D of HCl = 18.25 and air = 14.4. HCl gas is highly soluble in water.
Question 7
State why HCl gas forms a mist of droplets of HCl acid in moist air.
Answer
Due to high solubility, HCl gas fumes in moist air and forms a mist of droplets of HCl acid.
Question 8
State what the fountain experiment demonstrates with reference to HCl gas.
Answer
The high solubility of HCl gas in water is demonstrated by the Fountain experiment.
Question 9
State the colour change in three different indicators in presence of HCl gas.
Answer
Action on indicators:
Indicator | Original colour | Colour changed to |
---|---|---|
Moist litmus | Blue | Red |
Methyl orange | Orange | Pink |
Phenolphthalein (alkaline) | Pink | Colourless |
Question 10
Give a balanced equation for thermal dissociation of
(i) a gas
(ii) a solid [both containing the chloride ion].
Answer
(i)
(ii)
Question 11
Give the equation and state the observation seen when HCl gas reacts with ammonia.
Answer
NH3 [g] + HCl [g] ⟶ NH4Cl (s-solid)
When a gas jar containing HCl gas in inverted over a jar full of ammonia gas dense white fumes are formed. These fumes consists of particles of solid ammonium chloride suspended in air.
Question 12
Convert iron to iron (II) chloride using HCl gas.
Answer
Fe + 2HCl ⟶ FeCl₂ + H₂
Question 13
Explain the arrangement (i) not used (ii) used – for converting HCl gas into HCl acid.
Answer
Hydrochloric acid is prepared by dissolving hydrogen chloride gas in water using a special funnel arrangement.
(i) Direct absorption of HCl gas in water using a delivery tube causes back suction. Hence, it is not used for preparing HCl acid from HCl gas.
- Hydrogen chloride gas is extremely soluble in water.
- If a delivery tube through which HCl gas is passed is directly immersed in water, the rate of absorption of HCl gas is high and hence a partial vacuum is created in the tube.
- The pressure outside being higher causes the water to be pushed up into the delivery tube and damages the apparatus. This is called back-suction.
(ii) Special funnel arrangement is used for converting HCl gas into HCl acid as it avoids back suction. It:
(a) Prevents or minimizes back-suction of water.
(b) Provides a large surface area for absorption of HCl gas.
- The rim of the funnel is placed so that it just touches the trough containing water. If back-suction occurs, the water rises up the funnel and the level outside the funnel falls, creating an air gap between the rim of the funnel and the surface of water.
- The pressure outside and inside equalize and the water which had risen in the funnel falls down again. This process continues till the water in the trough is saturated with hydrogen chloride gas resulting in the formation of hydrochloric acid.
- Hence, hydrochloric acid is not prepared in the laboratory - by passing hydrogen chloride gas directly through water, but prepared using a special funnel arrangement.
Question 14
Explain the term 'constant boiling mixture'.
Answer
A solution which boils without any change in it's composition is known as the constant boiling mixture. A solution of HCl in water forms a constant boiling mixture at 110° C.
Question 15
State why dilute HCl cannot be concentrated beyond a certain concentration by boiling.
Answer
On boiling, the mixture evolves out the vapours of both acid and water in the same proportion as in the liquid. Hence, dilute HCl cannot be concentrated beyond a certain concentration by boiling.
Question 16
Name the ions obtained when HCl dissociates in aqueous solution.
Answer
The ions obtained are hydronium ions (H3O+) and chloride ions (Cl-)
HCl + H2O ⟶ H3O+ + Cl-
Question 17
Name the ion responsible for acidic nature of HCl acid.
Answer
The presence of hydrogen ions [H+] in HCl imparts acidic properties to an aqueous solution of hydrochloric acid.
Question 18
State which of two — a solution of HCl in water or in toluene is an electrolyte, giving reasons.
Answer
Water being a polar solvent, ionizes the polar covalent HCl molecule into free ions. Hence, the solution of HCl in water exhibits acidic properties and is an electrolyte whereas toluene not being a polar solvent does not dissociate HCl molecule into free ions. Hence, the solution of HCl in toluene does not exhibit acidic properties and is a non electrolyte.
Question 19
Give four different word equations relating to acidic properties of an aq. soln. of HCl gas.
Answer
- Magnesium + Hydrochloric acid ⟶ Magnesium chloride + Hydrogen
- Copper oxide + Hydrochloric acid ⟶ Copper chloride + Water
- Sodium carbonate + Hydrochloric acid ⟶ Sodium chloride + Water + Carbon dioxide gas
- Magnesium sulphite + Hydrochloric acid ⟶ Magnesium chloride + Water + sulphur dioxide gas
Question 20
Give balanced equations to obtain
(i) H2
(ii) CO2
(iii) SO2
(iv) H2S
from dil. HCl.
Answer
(i) Mg + 2HCl ⟶ MgCl2 + H2
(ii) NaHCO3 + HCl ⟶ NaCl + H2O + CO2 [g]
(iii) Na2SO3 + 2HCl ⟶ 2NaCl + H2O + SO2 [g]
(iv) FeS + 2HCl ⟶ FeCl2 + H2S
Question 21
Convert two soluble metallic nitrates to insoluble metallic chlorides using dil. HCl.
Answer
(i) AgNO3 + HCl ⟶ AgCl ↓ + HNO3
(ii) Pb(NO3)2 + 2HCl ⟶ PbCl2 ↓ + 2HNO3
Question 22
State how you would prove that HCl contains :
(i) hydrogen – using an active metal below magnesium
(ii) chlorine – using an oxidising agent not containing lead.
Answer
(i) Fe + 2HCl ⟶ FeCl2 + H2
(ii) MnO2 + 4HCl ⟶ MnCl2 + 2H2O + Cl2
Question 23
State the composition of aqua regia. State which component is the oxidising agent in aqua regia.
Answer
Aqua regia is a mixture of 1 part of conc. HNO3 and 3 parts of conc. HCl [by vol.]
Nitric acid is the oxidizing agent in aqua regia.
Question 24
Convert hydrochloric acid to nascent chlorine.
Answer
HNO3 + 3HCl ⟶ 2H2O + NOCl + 2[Cl] [nascent chlorine]
Question 25
State why aqua regia dissolves gold, which is insoluble in all other acids.
Answer
Aqua regia : 1 part of conc. HNO3 and 3 parts of conc. HCl
Nitric acid present in aqua regia oxidizes HCl to chlorine.
HNO3 + 3HCl ⟶ NOCl + 2H2O + 2[Cl] [nascent chlorine]
This nascent chlorine reacts with noble metals like gold forming the corresponding soluble chloride.
Au + 3[Cl] ⟶ AuCl3 [Gold (III) Chloride]
Hence, aqua regia dissolves noble metals like gold and platinum which are insoluble in all other acids.
Question 26
Give three tests for hydrochloric acid. Convert silver nitrate to a soluble salt of silver using hydrochloric acid and an alkali.
Answer
(i) When glass rod dipped in ammonia solution (NH4OH) is brought near vapours of hydrochloric acid, dense white fumes of ammonium chloride are formed.
(ii) On addition of silver nitrate soln. to dil. HCl (acidified with dil. HNO3), curdy white precipitate of silver chloride is obtained.
AgNO3 + HCl ⟶ AgCl ↓ + HNO3
(iii) On heating a mixture of manganese dioxide and conc. HCl, Greenish yellow gas (chlorine) is evolved.
MnO2 + 4HCl ⟶ MnCl2 ↓ + 2H2O + Cl2
Question 27
State two industrial products manufactured from hydrochloric acid, which are also manufactured from nitric and sulphuric acid. Give two general uses of hydrochloric acid.
Answer
Industrial products manufactured from HCl acid are :
- Dyes
- Paint
General uses of hydrochloric acid are :
- Hydrochloric acid dissolves the calcium phosphate present in bones. Hence, it is used in the extraction of glue from bones.
- Hydrochloric acid dissolves the metallic oxide coating [impurities] on the surface of the metal, thereby cleans the surface. Hence, it is used in pickling of metals before galvanizing.
Unit Test Paper 7A — Hydrogen Chloride
Question 1
Give balanced equations for the conversions A, B, C, D and E given below :
Answer
- A —
B — - C — NaHCO3 + HCl ⟶ NaCl + H2O + CO2
D — - E1 — 2Fe + 3Cl2 ⟶ 2FeCl3
E2 — Fe + 2HCl [g] ⟶ FeCl2 + H2 [g]
Question 2.1
Give reasons for the following :
In the laboratory preparation of HCl acid from NaCl and conc. H2SO4, the residual salt formed at temperatures above 200°C forms a hard crust and sticks to the glass.
Answer
At temperatures above 200°C, Sodium sulphate is formed. It forms a hard crust, sticks to the glass and is difficult to remove.
Question 2.2
Give reasons for the following :
Dense white fumes are obtained when a jar of HCl gas is inverted over a jar of ammonia gas.
Answer
When a gas jar containing HCl gas in inverted over a jar full of ammonia gas, dense white fumes are formed. These fumes consists of particles of solid ammonium chloride suspended in air.
NH3 [g] + HCl [g] ⟶ NH4Cl (s-solid)
Question 2.3
Give reasons for the following :
In the fountain experiment to demonstrate the high solubility of HCl gas in water, dry HCl gas is filled in the round bottom flask.
Answer
HCl gas present in the flask dissolves in water due to high solubility, creating a partial vacuum in the flask. The outside pressure being higher pushes the blue litmus solution up the jet tube which emerges out at the end of the tube as red fountain. Hence, the inference is that the HCl gas is highly soluble in water and acidic in nature.
Question 2.4
Give reasons for the following :
Iron sheets are cleaned with hydrochloric acid before dipping into molten zinc for galvanizing.
Answer
Hydrochloric acid dissolves the metallic oxide coating [impurities] on the surface of the metal, thereby cleans the metallic surface before galvanizing.
Question 2.5
Give reasons for the following :
Hydrogen chloride gas fumes in moist air but hydrogen sulphide gas does not.
Answer
Due to the high solubility of HCl gas, it fumes in moist air and forms a mist of droplets of HCl acid. On the other hand, Hydrogen Sulphide does not do so as it is slightly soluble in water.
Question 3
Complete the statements given below using the correct word/s
- An aqueous solution of HCl gas is named ............... [aqua fortis / muriatic acid / oil of vitriol]
- The salt obtained when rock salt reacts with conc. H2SO4 at temperatures below 200°C is a/an ............... [acid/normal] salt.
- In the preparation of HCl acid from HCl gas, a funnel arrangement provides ............... [less/more] surface area for absorption of the gas.
- The ions which impart acidic properties to an aqueous solution of hydrogen chloride are ............... [chloride/hydrogen/hydronium]
- The indicator which does not change colour on passage of hydrogen chloride gas is ............... [moist blue litmus / phenolphthalein / methyl orange].
Answer
- An aqueous solution of HCl gas is named muriatic acid.
- The salt obtained when rock salt reacts with conc. H2SO4 at temperatures below 200°C is an acid salt.
- In the preparation of HCl acid from HCl gas, a funnel arrangement provides more surface area for absorption of the gas.
- The ions which impart acidic properties to an aqueous solution of hydrogen chloride are hydrogen.
- The indicator which does not change colour on passage of hydrogen chloride gas is phenolphthalein.
Question 4
Choose from the letters A, B, C, D and E, to match the descriptions 1 to 5 given below.
A : NH4Cl
B : AgCl
C : PbCl2
D : FeCl2
E : Ag(NH3)2Cl
- A soluble salt obtained on reaction of a metallic chloride with liquor ammonia.
- A salt which is insoluble in dilute nitric acid but soluble in ammonium hydroxide.
- A salt obtained on reaction of an active metal with hydrogen chloride gas.
- A salt obtained when a basic gas reacts with hydrogen chloride gas.
- A salt soluble in hot water but not in cold, obtained on heating an oxidising agent with conc. HCl.
Answer
- A soluble salt obtained on reaction of a metallic chloride with liquor ammonia — E : [Ag(NH3)2Cl]
- A salt which is insoluble in dilute nitric acid but soluble in ammonium hydroxide. — B : AgCl
- A salt obtained on reaction of an active metal with hydrogen chloride gas. — D : FeCl2
- A salt obtained when a basic gas reacts with hydrogen chloride gas. — A : NH4Cl
- A salt soluble in hot water but not in cold, obtained on heating an oxidising agent with conc. HCl. — C : PbCl2
Question 5
Select the correct word or formula from the same given in bracket :
- The substance reacted with conc. HCl and heated to prove that conc. HCl contains Cl2. [PbCl2/PbO2/PbO]
- The metal reacted with dil. HCl to prove that dil. HCl contains hydrogen. [Cu/Fe/Ag/Pb]
- The gas/es which is/are heavier than air and highly soluble in water. [NH3/HCl/CO2/H2S]
- The acid which is not an oxidizing agent. [Conc. HNO3 / Conc. HCl / Conc. H2SO4]
- The acid which is not a monobasic acid. [Acetic/Sulphurous/Hydrochloric/Nitric/Formic acid]
Answer
- The substance reacted with conc. HCl and heated to prove that conc. HCl contains Cl2. — PbO2
- The metal reacted with dil. HCl to prove that dil. HCl contains hydrogen. — Fe
- The gases which are heavier than air and highly soluble in water. — HCl and NH3
- The acid which is not an oxidizing agent. — Conc. HCl
- The acid which is not a monobasic acid. — Sulphurous acid
Question 6
Select the correct words from the list given below to complete the following word equations :
Metallic oxide, active metal, metallic carbonate, metallic bisulphite, active metal, metallic hydroxide, metallic bicarbonate, metallic sulphate, metallic sulphide.
- ............... + hydrochloric acid (dil) ⟶ salt + hydrogen
- ............... + hydrochloric acid (dil) ⟶ salt + water
- ............... + hydrochloric acid (dil) ⟶ salt + water + carbon dioxide
- ............... + hydrochloric acid (dil) ⟶ salt + water + sulphur dioxide
- ............... + hydrochloric acid (dil) ⟶ salt + hydrogen sulphide
Answer
- Active metal + hydrochloric acid (dil) ⟶ salt + hydrogen
- Metallic oxide, hydroxide + hydrochloric acid (dil) ⟶ salt + water
- Metallic carbonate / bicarbonate + hydrochloric acid (dil) ⟶ salt + water + carbon dioxide
- Metallic bisulphite + hydrochloric acid (dil) ⟶ salt + water + sulphur dioxide
- Metallic sulphide + hydrochloric acid (dil) ⟶ salt + hydrogen sulphide