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Class - 12 CBSE Computer Science Important Output Questions 2025

  • SQL Queries

    Consider the table CLUB given below and write the output of the SQL queries that follow.

    CIDCNAMEAGEGENDERSPORTSPAYDOAPP
    5246AMRITA35FEMALECHESS9002006-03-27
    4687SHYAM37MALECRICKET13002004-04-15
    1245MEENA23FEMALEVOLLEYBALL10002007-06-18
    1622AMRIT28MALEKARATE10002007-09-05
    1256AMINA36FEMALECHESS11002003-08-15
    1720MANJU33FEMALEKARATE12502004-04-10
    2321VIRAT35MALECRICKET10502005-04-30

    (i) SELECT COUNT(DISTINCT SPORTS) FROM CLUB;

    (ii) SELECT CNAME, SPORTS FROM CLUB WHERE DOAPP<"2006-04-30" AND CNAME LIKE "%NA";

    (iii) SELECT CNAME, AGE, PAY FROM CLUB WHERE GENDER = "MALE" AND PAY BETWEEN 1000 AND 1200;


  • SQL Queries

    Give output for following SQL queries as per given table(s) :

    Table : GARMENT

    GCODEDescriptionPriceFCODEREADYDATE
    10023PENCIL SKIRT1150F0319-DEC-08
    10001FORMAL SHIRT1250F0112-JAN-08
    10012INFORMAL SHIRT1550F0206-JUN-08
    10024BABY TOP750F0307-APR-07
    10090TULIP SKIRT850F0231-MAR-07
    10019EVENING GOWN850F0306-JUN-08
    10009INFORMAL PANT1500F0220-OCT-08
    10017FORMAL PANT1350F0109-MAR-08
    10020FROCK850F0409-SEP-07
    10089SLACKS750F0331-OCT-08

    Table : FABRIC

    FCODETYPE
    F04POLYSTER
    F02COTTON
    F03SILK
    F01TERELENE

    (i) SELECT SUM(PRICE) FROM GARMENT WHERE FCODE = 'F01' ;

    (ii) SELECT DESCRIPTION, TYPE FROM GARMENT, FABRIC
    WHERE GARMENT.FCODE = FABRIC.FCODE AND GARMENT.PRICE >= 1260 ;

    (iii) SELECT MAX(FCODE) FROM FABRIC ;

    (iv) SELECT COUNT(DISTINCT PRICE) FROM GARMENT ;


  • SQL Queries

    Give output for following SQL queries as per given table(s) :

    Table : PRODUCT

    P_IDProductNameManufacturerPrice
    TPO1Talcom PowderLAK40
    FW05Face WashABC45
    BS01Bath SoapABC55
    SHO6ShampooXYZ120
    FW12Face WashXYZ95

    Table : CLIENT

    C_IDClientNameCityP_ID
    01Cosmetic ShopDelhiFW05
    06Total HealthMumbaiBS01
    12Live LifeDelhiSHO6
    15Pretty WomanDelhiFW12
    16DreamsBangaloreTP01

    (i) SELECT DISTINCT City FROM Client ;

    (ii) SELECT Manufacturer, MAX(Price), Min(Price), Count(*)
    FROM Product GROUP BY Manufacturer ;

    (iii) SELECT ClientName, ProductName
    FROM Product, Client
    WHERE Client.P_Id = Product.P_Id ;

    (iv) SELECT ProductName, Price * 4 FROM Product ;


  • SQL Queries

    Give output for following SQL queries as per given table(s) :

    Table : ITEM

    I_IDItemNameManufacturerPrice
    PC01Personal ComputerABC35000
    LC05LaptopABC55000
    PC03Personal ComputerXYZ32000
    PC06Personal ComputerCOMP37000
    LC03LaptopPQR57000

    Table : CUSTOMER

    C_IDCustomerNameCityI_ID
    01N RoyDelhiLC03
    06H SinghMumbaiPC03
    12R PandeyDelhiPC06
    15C SharmaDelhiLC03
    16K AgarwalBangalorePC01

    (i) SELECT DISTINCT City FROM Customer ;

    (ii) SELECT ItemName, MAX(Price), Count(*)
    FROM Item GROUP BY ItemName ;

    (iii) SELECT CustomerName, Manufacturer
    FROM Item, Customer
    WHERE Item.I_ID = Customer.I_ID ;

    (iv) SELECT ItemName, Price * 100
    FROM Item WHERE Manufacturer = 'ABC' ;


  • SQL Queries

    Give output for following SQL queries as per given table(s) :

    Table : SENDER

    SenderIDSenderNameSenderAddressSenderCity
    ND01R Jain2, ABC ApptsNew Delhi
    MU02H Sinha12, NewtownMumbai
    MU15S Jha27/A, Park StreetMumbai
    ND50T Prasad122-K, SDANew Delhi

    Table : RECIPIENT

    RecIDSenderIDRecNameRecAddressRecCity
    KO05ND01R Bajpayee5, Central AvenueKolkata
    ND08MU02S Mahajan116, A ViharNew Delhi
    MU19ND01H Singh2A, Andheri EastMumbai
    MU32MU15P K SwamyB5, C S TerminusMumbai
    ND48ND50S Tripathi13, B1 D, Mayur ViharNew Delhi

    (i) SELECT DISTINCT SenderCity FROM Sender ;

    (ii) SELECT A.SenderName, B.RecName
    FROM Sender A, Recipient B
    WHERE A.SenderID = B.SenderID AND B.RecCity = 'Mumbai' ;

    (iii) SELECT RecName, RecAddress FROM Recipient
    WHERE RecCity NOT IN('Mumbai', 'Kolkata') ;

    (iv) SELECT RecID, RecName FROM Recipient
    WHERE SenderID = 'MU02' OR SenderID = 'ND50' ;


  • SQL Queries

    Given the table LIBRARY :

    NoTitleAuthorTypePubQtyPrice
    1Data StructureLipschutzDSMcGraw4217
    2Computer StudiesFrenchFNDGalgotia275
    3Advanced PascalSchildtPROGMcGraw4350
    4Dbase dummiesPalmerDBMSPustakM5130
    5Mastering C + +GurewichPROGBPB3295
    6Guide NetworkFreedNETZPress3200
    7Mastering FoxproSeigalDBMSBPB2135
    8DOS guideNortonOSPHI3175
    9Basic for BeginnersMortonPROGBPB340
    10Mastering WindowCowartOSBPB1225

    Give the output of following SQL commands on the basis of table Library.

    (i) SELECT UPPER(Title) FROM Library WHERE Price < 150 ;

    (ii) SELECT CONCAT(Author, Type) FROM Library WHERE Qty < 3 ;

    (iii) SELECT MOD(Qty, 4) FROM Library ;


  • SQL Queries

    Given the following table :

    Table : STUDENT1

    No.NameStipendStreamAvgMarkGradeClass
    1Karan400.00Medical78.5B12B
    2Divakar450.00Commerce89.2A11C
    3Divya300.00Commerce68.6C12C
    4Arun350.00Humanities73.1B12C
    5Sabina500.00Nonmedical90.6A11A
    6John400.00Medical75.4B12B
    7Robert250.00Humanities64.4C11A
    8Rubina450.00Nonmedical88.5A12A
    9Vikas500.00Nonmedical92.0A12A
    10Mohan300.00Commerce67.5C12C

    Give the output of following SQL statement :

    (i) SELECT TRUNCATE(AvgMark) FROM Student1 WHERE AvgMark < 75 ;

    (ii) SELECT ROUND(AvgMark) FROM Student1 WHERE Grade = 'B' ;

    (iii) SELECT CONCAT(Name, Stream) FROM Student1 WHERE Class = '12A' ;

    (iv) SELECT RIGHT(Stream, 2) FROM Student1 ;


  • SQL Queries

    The Doc_name Column of a table Hospital is given below :

    Doc_name
    Avinash
    Hariharan
    Vinayak
    Deepak
    Sanjeev

    Based on the information, find the output of the following queries :

    (i) SELECT docname FROM HOSPITAL WHERE Docname like "%v";

    (ii) SELECT docname FROM HOSPITAL WHERE docname like "%e%";


  • SQL Queries

    Predict the output of the following queries based on the table CAR_SALES given below :

    NUMBERSEGMENTFUELQT1QT2
    1Compact HatchBackPetrol5600070000
    2Compact HatchBackDiesel3400040000
    3MUVPetrol3300035000
    4MUVDiesel1400015000
    5SUVPetrol2700054000
    6SUVDiesel1800030000
    7SedanPetrol800010000
    8SedanDiesel10005000

    (i) SELECT LEFT(SEGMENT, 2) FROM CAR_SALES WHERE FUEL= "PETROL";

    (ii) SELECT (QT2-QT1)/2 "AVG SALE" FROM CAR_SALES WHERE SEGMENT= "SUV";

    (iii) SELECT SUM(QT1) "TOT SALE" FROM CAR_SALES WHERE FUEL= "DIESEL";


  • SQL Queries

    What will be the output of following code ?

    mysql> SELECT CONCAT(CONCAT('Inform', 'atics'), 'Practices');
    

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