Using remainder theorem, factorise 6x 3 - 11x 2 - 3x + 2 completely.

Substituting, x = 2 in 6x 3 - 11x 2 - 3x + 2, we get : ⇒ 6(2) 3 - 11(2) 2 - 3(2) + 2 ⇒ 6 × 8 - 11 × 4 - 6 + 2 ⇒ 48 - 44 - 6 + 2 ⇒ 6 - 6 ⇒ 0. ∴ (x - 2) is a factor of 6x 3 - 11x 2 - 3x + 2. On dividing 6x 3 - 11x 2 - 3x + 2 by (x - 2), we get: ∴ 6x 3 - 11x 2 - 3x + 2 = (x - 2)(6x 2 + x - 1) ⇒ 6x 3 - 11x 2 - 3x + 2 = (x - 2)(6x 2 + 3x - 2x - 1) ⇒ 6x 3 - 11x 2 - 3x + 2 = (x - 2)[3x(2x + 1) - 1(2x + 1)] ⇒ 6x 3 - 11x 2 - 3x + 2 = (x - 2)(3x - 1)(2x + 1). Hence, 6x 3 - 11x 2 - 3x + 2 = (x - 2)(3x - 1)(2x + 1).

In the given figure, AB is diameter and PC is tangent to the circle with center O. If AP = 40 cm, CP = 20 cm, find the radius of the circle.

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In rhombus ABCD, the co-ordinates of point A and C are (2, -6) and (-4, 8) respectively. Find the equation of the diagonal BD.

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Mathematics

Using remainder theorem, factorise 6x³ - 11x² - 3x + 2 completely.

Factorisation

Related Questions

In the given figure, AB is diameter and PC is tangent to the circle with center O. If AP = 40 cm, CP = 20 cm, find the radius of the circle.

In rhombus ABCD, the co-ordinates of point A and C are (2, -6) and (-4, 8) respectively. Find the equation of the diagonal BD.

Mathematics

Using remainder theorem, factorise 6x3 - 11x2 - 3x + 2 completely.

Factorisation

Related Questions

In the given figure, AB is diameter and PC is tangent to the circle with center O. If AP = 40 cm, CP = 20 cm, find the radius of the circle.

In rhombus ABCD, the co-ordinates of point A and C are (2, -6) and (-4, 8) respectively. Find the equation of the diagonal BD.

Using remainder theorem, factorise 6x³ - 11x² - 3x + 2 completely.