Mathematics

Triangles ABC and PQR are similar to each other, then : 1. Ar.(△ABC)/Ar.(△PQR) = BC^2/PQ^2 2. AB^2/PQ^2 = AC^2/PR^2 3. Ar.(△BAC)/Ar.(△QPR) ≠ AB^2/QP^2 4. AC^2/PR^2 = BC^2/PQ^2

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