Triangles ABC and PQR are similar to each other, then :

1. $\dfrac{\text{Ar.(△ABC)}}{\text{Ar.(△PQR)}} = \dfrac{BC^2}{PQ^2}$

2. $\dfrac{AB^2}{PQ^2} = \dfrac{AC^2}{PR^2}$

3. $\dfrac{\text{Ar.(△BAC)}}{\text{Ar.(△QPR)}} \ne \dfrac{AB^2}{QP^2}$

4. $\dfrac{AC^2}{PR^2} = \dfrac{BC^2}{PQ^2}$

In the given figure, EF is parallel to BC. If area of triangle ABC is 576 cm², the area of triangle AEF is :

1. 128 cm²

2. 288 cm²

3. 256 cm²

4. 768 cm²

In the following figure, XY is parallel to BC, AX = 9 cm, XB = 4.5 cm and BC = 18 cm.

Find:

(i) $\dfrac{AY}{YC}$

(ii) $\dfrac{YC}{AC}$

(iii) XY

The model of a ship is made to a scale of 3 : 500. If the length of the model is 1.5 m, the length of ship is :

1. 750 m

2. 1000 m

3. 450 m

4. 250 m