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Triangle ABC is similar to triangle PQR. If AD and PM are altitudes of the two triangles, prove that: ABPQ=ADPM\dfrac{AB}{PQ} = \dfrac{AD}{PM}.

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Answer

Given, ∆ABC ~ ∆PQR

Triangle ABC is similar to triangle PQR. If AD and PM are altitudes of the two triangles, prove that: AB/PQ = AD/PM. Similarity, Concise Mathematics Solutions ICSE Class 10.

So,

∠ABC = ∠PQR i.e., ∠ABD = ∠PQM

Also, ∠ADB = ∠PMQ [Both are right angles]

∴ ∆ABD ~ ∆PQM [By AA]

Since, corresponding sides of similar triangles are proportional.

ABPQ=ADPM\dfrac{AB}{PQ} = \dfrac{AD}{PM}.

Hence, proved that ABPQ=ADPM\dfrac{AB}{PQ} = \dfrac{AD}{PM}.

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