Physics
Three resistors of 6.0 Ω, 2.0 Ω and 4.0 Ω are joined to an ammeter A and a cell of e.m.f. 6.0 V as shown in figure. Calculate —
(a) the effective resistance of the circuit, and
(b) the reading of ammeter.
Current Electricity
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Answer
In the circuit, there are two parts. In the first part, resistors of 2.0 and 4.0 Ω are connected in series. If the equivalent resistance of this part is Rs then
Rs = 2 + 4 = 6 Ω
In the second part, Rs = 6.0 and resistor of 6.0 Ω are connected in parallel. If the equivalent resistance of this part is Rp then
Hence, the effective resistance of the circuit = 3 Ω
(b) The reading of ammeter = ?
R = 3 Ω
V = 6.0 V
Using Ohm's law,
V = IR
Substituting the values in the formula above we get,
6 = I x 3
⇒ I = 6 / 3 = 2 A
Hence, the reading of ammeter = 2 A
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