Mathematics
The following figure shows a triangle ABC in which AD and BE are perpendiculars to BC and AC respectively.
Show that :
(i) △ADC ~ △BEC
(ii) CA × CE = CB × CD
(iii) △ABC ~ △DEC
(iv) CD × AB = CA × DE
![The figure shows a triangle ABC in which AD and BE are perpendiculars to BC and AC respectively. Show that (i) △ADC ~ △BEC (ii) CA × CE = CB × CD (iii) △ABC ~ △DEC (iv) CD × AB = CA × DE. Similarity, Concise Mathematics Solutions ICSE Class 10.](https://cdn1.knowledgeboat.com/img/cm10/q24-c15-ex-15-e-similarity-concise-maths-solutions-icse-class-10-998x631.png)
Related Questions
In the given figure, ABC is a right angled triangle with ∠BAC = 90°.
(i) Prove that : △ADB ~ △CDA.
(ii) If BD = 18 cm and CD = 8 cm, find AD.
(iii) Find the ratio of the area of △ADB is to area of △CDA.
ABC is a right angled triangle with ∠ABC = 90°. D is any point on AB and DE is perpendicular to AC. Prove that :
(i) △ADE ~ △ACB
(ii) If AC = 13 cm, BC = 5 cm and AE = 4 cm. Find DE and AD.
(iii) Find, area of △ADE : area of quadrilateral BCED.