Mathematics
The figure (iii) given below show the cross-section of a swimming pool 10 m broad, 2 m deep at one end and 3 m deep at the other end. Calculate the volume of water it will hold when full, given that its length is 40 m.
Mensuration
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Answer
Figure (iii) is a trapezium with parallel sides 2 m and 3m.
By formula,
Area of cross section = (sum of parallel sides) × distance between them
= (2 + 3) × 40
= × 5 × 40
= 100 m2.
So, the volume of water it will hold when full = area of cross section × width
= 100 × 10
= 1000 m3.
Hence, swimming pool will hold 1000 m3 of water.
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