Mathematics
A swimming pool is 50 metres long and 15 metres wide. Its shallow and deep ends are metres and metres deep respectively. If the bottom of the pool slopes uniformly, find the amount of water required to fill the pool.
Mensuration
15 Likes
Answer
Given,
Length of swimming pool = 50 m
Width of swimming pool = 15 m
Its shallow and deep ends are 1.5 m and 4.5 m deep
By formula,
Area of cross section of swimming pool = (sum of parallel sides) × length
=
= × 6 × 50
= 150 m2.
Amount of water required to fill pool = Area of cross section × width
= 150 × 15
= 2250 m3.
Hence, amount of water required to fill pool 2250 m3.
Answered By
10 Likes
Related Questions
The area of cross-section of a pipe is 3.5 cm2 and water is flowing out of pipe at the rate of 40 cm/s. How much water is delivered by the pipe in one minute?
The figure (iii) given below show the cross-section of a swimming pool 10 m broad, 2 m deep at one end and 3 m deep at the other end. Calculate the volume of water it will hold when full, given that its length is 40 m.
The figure (i) given below shows a solid of uniform cross-section. Find the volume of the solid. All measurements are in cm and all angles in the figure are right angles.
The figure (ii) given below shows the cross section of a concrete wall to be constructed. It is 2 m wide at the top, 3.5 m wide at the bottom and its height is 6 m and its length is 400 m. Calculate
(i) the cross sectional area and
(ii) volume of concrete in the wall.
