The circumference of the edge of a hemispherical bowl is 132 cm. Find the capacity of the bowl.

Circumference of the edge of bowl = 132 cm.

$\therefore 2πr = 132 \\[1em] \Rightarrow 2 \times \dfrac{22}{7} \times r = 132 \\[1em] r = \dfrac{132 \times 7}{22 \times 2} \\[1em] r = 3 \times 7 \\[1em] r = 21 \text{ cm}.$

Volume of hemispherical bowl (V) = $\dfrac{2}{3}πr^3$

Putting values we get,

$V = \dfrac{2}{3} \times \dfrac{22}{7} \times (21)^3 \\[1em] = \dfrac{2 \times 22 \times 21^3}{21} \\[1em] = 2 \times 22 \times 441 \\[1em] = 19404 \text{ cm}^3.$

Hence, the capacity of bowl = 19404 cm³.