In the given figure, BC is parallel to DE. Area of triangle ABC = 25 cm 2 , Area of trapezium BCED = 24 cm 2 and DE = 14 cm. Calculate the length of BC. Also, find the area of triangle BCD.

Area of △ADE = Area of △ABC + Area of trapezium BCED = 25 + 24 = 49 cm 2 . Given, BC || DE. ∠ABC = ∠ADE [Corresponding angles are equal] ∠ACB = ∠AED [Corresponding angles are equal] ∴ △ABC ~ △ADE [By AA] We know that, The ratio of the areas of two similar triangles is equal to the ratio of squares of their corresponding sides. Let height of trapezium BCED be h cm. Area = × (Sum of || sides) × h ⇒ 24 = × (BC + DE) × h ⇒ 24 × 2 = (BC + DE) × h ⇒ 48 = (10 + 14) × h ⇒ 24h = 48 ⇒ h = 2 cm. Area of △BCD = × base × height = × BC × h = × 10 × 2 = 10 cm 2 . Hence, BC = 10 cm and area of △BCD = 10 cm 2 .

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Mathematics

In the given figure, BC is parallel to DE. Area of triangle ABC = 25 cm², Area of trapezium BCED = 24 cm² and DE = 14 cm. Calculate the length of BC.
Also, find the area of triangle BCD.

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Mathematics

In the given figure, BC is parallel to DE. Area of triangle ABC = 25 cm², Area of trapezium BCED = 24 cm² and DE = 14 cm. Calculate the length of BC.
Also, find the area of triangle BCD.

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Mathematics

In the given figure, BC is parallel to DE. Area of triangle ABC = 25 cm2, Area of trapezium BCED = 24 cm2 and DE = 14 cm. Calculate the length of BC.Also, find the area of triangle BCD.

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In the given figure, BC is parallel to DE. Area of triangle ABC = 25 cm², Area of trapezium BCED = 24 cm² and DE = 14 cm. Calculate the length of BC.
Also, find the area of triangle BCD.

In the given figure,
∠B = ∠E, ∠ACD = ∠BCE, AB = 10.4 cm and DE = 7.8 cm. Find the ratio between areas of the △ABC and △DEC.

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(i) area of triangle CDP,
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