In the given figure, ∠B = ∠E, ∠ACD = ∠BCE, AB = 10.4 cm and DE = 7.8 cm. Find the ratio between areas of the △ABC and △DEC.

Given, ⇒ ∠ACD = ∠BCE ⇒ ∠ACD + ∠BCD = ∠BCE + ∠BCD ⇒ ∠ACB = ∠DCE Also, ∠B = ∠E ∴ △ABC ~ △DEC [By AA] We know that, The ratio of the areas of two similar triangles is equal to the ratio of squares of their corresponding sides. Hence, ratio between areas of the △ABC and △DEC = 16 : 9.