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In the following figure, a circle is inscribed in the quadrilateral ABCD. If BC = 38 cm, QB = 27 cm, DC = 25 cm and that AD is perpendicular to DC, find the radius of the circle.

In the figure, a circle is inscribed in the quadrilateral ABCD. If BC = 38 cm, QB = 27 cm, DC = 25 cm and that AD is perpendicular to DC, find the radius of the circle. Tangents and Intersecting Chords, Concise Mathematics Solutions ICSE Class 10.

Circles

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Answer

From figure,

⇒ BR = BQ = 27 cm [∵ Length of tangents form an external point to a circle are equal.]

⇒ CR = BC - BR = 38 - 27 = 11 cm.

⇒ CR = CS = 11 cm [∵ Length of tangents form an external point to a circle are equal.]

⇒ DS = DC - CS = 25 - 11 = 14 cm.

In quadrilateral DSOP,

⇒ ∠SDP + ∠DPO + ∠OSD + ∠POS = 360°

⇒ 90° + 90° + 90° + ∠POS = 360°

⇒ ∠POS = 360° - 270° = 90°.

Since, all angles are 90° and OS = OP [∵ Both equal to radius of same circle]

Hence, proved that DPOS is a square.

OP = DS = 14 cm.

Hence, radius of circle = 14 cm.

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