Mathematics
In the figure (i) given below, PQRS is a cyclic quadrilateral in which PQ = QR and RS is produced to T. If ∠QPR = 52°, calculate ∠PST.
Circles
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Answer
Given, ∠QPR = 52°.
Since PQ = PR so, ∠QRP = ∠QPR = 52°.
Since sum of angles of triangle = 180°
In △PQR
⇒ ∠QPR + ∠QRP + ∠PQR = 180°
⇒ 52° + 52° + ∠PQR = 180°
⇒ 104° + ∠PQR = 180°
⇒ ∠PQR = 180° - 104°
⇒ ∠PQR = 76°.
∵ exterior angle of a cyclic quadrilateral is equal to the opposite interior angle.
∠PST = ∠PQR = 76°
Hence, the value of ∠PST = 76°
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