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In the figure (i) given below, calculate the area of the shaded region correct to two decimal places. (Take π = 3.142)

In the figure, calculate the area of the shaded region correct to two decimal places. Mensuration, ML Aggarwal Understanding Mathematics Solutions ICSE Class 9.

Mensuration

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Answer

From figure,

O is the center. In right angle triangle ABC,

In the figure, calculate the area of the shaded region correct to two decimal places. Mensuration, ML Aggarwal Understanding Mathematics Solutions ICSE Class 9.

Using pythagoras theorem,

⇒ AC2 = AB2 + BC2

⇒ AC2 = 52 + 122

⇒ AC2 = 25 + 144 = 169

⇒ AC = 169\sqrt{169} = 13 cm.

From figure,

AC is the diameter and OA is the radius = 132\dfrac{13}{2} = 6.5 cm.

Area of circle = πr2

= 3.142 × (6.5)2

= 3.142 × 42.25

= 132.75 cm2.

Area of rectangle = l × b

= 12 × 5 = 60 cm2.

Area of shaded region = Area of circle - Area of rectangle

= 132.75 - 60

= 72.75 cm2.

Hence, area of shaded region = 72.75 cm2.

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