In the figure (2) given below, PQRS and ABRS are parallelograms, and X is any point on the side BR. Show that area of ∆AXS = area of || gm PQRS.

From figure, Since, PB is a straight line and PQ || SR so, PB || SR. || gm PQRS and ABRS are on the same base SR and between the same parallel lines PB and SR. So, Area of ||gm PQRS = Area of ||gm ABRS .........(i) ∆AXS and || gm ABRS are on the same base AS and between the same parallel lines AS and BR. So, Area of ∆AXS = Area of ||gm ABRS = area of ||gm PQRS [From (i)] Hence, proved that Area of ∆AXS = Area of || gm PQRS.

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In figure (1) given below, ABCD is a parallelogram. P, Q are any two points on the sides AB and BC respectively. Prove that
area of ∆CPD = area of ∆AQD.

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Mathematics

In the figure (2) given below, PQRS and ABRS are parallelograms, and X is any point on the side BR. Show that area of ∆AXS = area of || gm PQRS.

Theorems on Area

Related Questions

In figure (1) given below, ABCD is a parallelogram. P, Q are any two points on the sides AB and BC respectively. Prove that
area of ∆CPD = area of ∆AQD.

Mathematics

In the figure (2) given below, PQRS and ABRS are parallelograms, and X is any point on the side BR. Show that area of ∆AXS = area of || gm PQRS.

Theorems on Area

Related Questions

In figure (1) given below, ABCD is a parallelogram. P, Q are any two points on the sides AB and BC respectively. Prove thatarea of ∆CPD = area of ∆AQD.

In figure (1) given below, ABCD is a parallelogram. P, Q are any two points on the sides AB and BC respectively. Prove that
area of ∆CPD = area of ∆AQD.