Mathematics
In figure (1) given below, ABCD is a parallelogram. P, Q are any two points on the sides AB and BC respectively. Prove that
area of ∆CPD = area of ∆AQD.
Theorems on Area
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Answer
∆CPD and || gm ABCD are on the same base CD and between the same parallel lines AB and CD.
Area of ∆CPD = Area of ||gm ABCD …….(i)
∆AQD and || gm ABCD are on the same base AD and between the same parallel lines AD and BC.
Area of ∆AQD = Area of ||gm ABCD …….(ii)
From (i) and (ii)
Area of ∆CPD = Area of ∆AQD
Hence, proved that area of ∆CPD = area of ∆AQD.
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In the figure (2) given below, O is any point inside a parallelogram ABCD. Prove that
(i) area of ∆OAB + area of ∆OCD = area of || gm ABCD.
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