Mathematics
In figure (2) given below, area of ∆ABD is 24 sq. units. If AB = 8 units, find the height of △ABC.
Theorems on Area
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Answer
Given,
Area of ∆ABD = 24 sq. units
As ∆ABD and ∆ABC lie on same base AB and between same parallel lines AB and CD so,
Area of ∆ABC = Area of ∆ABD = 24 sq. units.
⇒ × AB × height = 24
⇒ × 8 × height = 24
⇒ 4 × height = 24
⇒ Height =
⇒ Height = 6 units.
Hence, height of ∆ABC = 6 units.
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