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Mathematics

If the line y = mx + c passes through the points (2, -4) and (-3, 1), determine the values of m and c.

Straight Line Eq

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Answer

Equation of line passing through (2, -4) and (-3, 1) i.e. two points can be given by two-point formula i.e.

yy1=y2y1x2x1(xx1)y(4)=1(4)32(x2)y+4=55(x2)y+4=1(x2)y+4=x+2y=x2.\Rightarrow y - y1 = \dfrac{y2 - y1}{x2 - x1}(x - x1) \\[1em] \therefore y - (-4) = \dfrac{1 - (-4)}{-3 - 2}(x - 2) \\[1em] \Rightarrow y + 4 = \dfrac{5}{-5}(x - 2) \\[1em] \Rightarrow y + 4 = -1(x - 2) \\[1em] \Rightarrow y + 4 = -x + 2 \\[1em] \Rightarrow y = -x - 2.

Comparing the above equation with y = mx + c we get,

m = -1 and c = -2.

Hence, the value of m is -1 and c is -2.

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