Write down the gradient and the intercept on the y-axis of the line 3y + 2x = 12.

Given, 3y + 2x = 12

⇒ 3y = -2x + 12

⇒ y = $-\dfrac{2}{3}x + 4$

Comparing the above equation with y = mx + c we get,

m = $-\dfrac{2}{3}$ and c = 4.

Hence, the gradient and intercept on the y-axis of the line 3y + 2x = 12 is $-\dfrac{2}{3}$ and 4 respectively.