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Mathematics

If discriminant of a quadratic equation ax2 + bc + c = 0 is equal to zero, then the roots of the equation are :

  1. b2a-\dfrac{b}{2a} each

  2. b2a\dfrac{b}{2a} each

  3. a2b-\dfrac{a}{2b} each

  4. b2b\dfrac{b}{2b} each

Quadratic Equations

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Answer

We know that,

x = b±b24ac2a\dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} …….(1)

Discriminant = b2 - 4ac = 0

Substituting value of discriminant in equation (1), we get :

x=b±02a=b2a.x = \dfrac{-b \pm \sqrt{0}}{2a} \\[1em] = \dfrac{-b}{2a}.

Hence, Option 1 is the correct option.

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