Mathematics
If matrix M = }[r] 1 & 3 \ -2 & 5 \end{bmatrix}, then the matrix -2M + 2I is :
}[r] 0 & -6 \ 4 & -8 \end{bmatrix}
}[r] 0 & -4 \ 6 & 8 \end{bmatrix}
}[r] 4 & 12 \ 0 & -4 \end{bmatrix}
}[r] -4 & 0 \ -8 & 6 \end{bmatrix}
Matrices
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Answer
I = }[r] 1 & 0 \ 0 & 1 \end{bmatrix}
Solving, -2M + 2I
}[r] 1 & 3 \ -2 & 5 \end{bmatrix} + 2\begin{bmatrix}[r] 1 & 0 \ 0 & 1 \end{bmatrix} \\[1em] \Rightarrow \begin{bmatrix}[r] -2 & -6 \ 4 & -10 \end{bmatrix} + \begin{bmatrix}[r] 2 & 0 \ 0 & 2 \end{bmatrix} \\[1em] \Rightarrow \begin{bmatrix}[r] -2 + 2 & -6 + 0 \ 4 + 0 & -10 + 2 \end{bmatrix} \\[1em] \Rightarrow \begin{bmatrix}[r] 0 & -6 \ 4 & -8 \end{bmatrix}
Hence, Option 1 is the correct option.
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