In the figure, given below, the medians BD and CE of a triangle ABC meet at G. Prove that :

(i) △EGD ~ △CGB and

(ii) BG = 2GD from (i) above.

In the given figure, DE is parallel to BC. If AD : BD = 3 : 5 then DE : BC is :

1. 3 : 8

2. 3 : 5

3. 5 : 3

4. 8 : 3

In the given figure,

AB = 10 cm, CD = 8 cm = OB, then OD is equal to :

1. 10 cm

2. 3.2 cm

3. 6.4 cm

4. 8 cm

In the given figure, AE : EC = 2 : 3 and BC = 20 cm then DE is equal to :

1. 10 cm

2. 12 cm

3. 8 cm

4. 16 cm