Mathematics
Given △ABC ~ △PQR, area of △ABC = 54 cm<sup>2</sup> and area of △PQR = 24 cm<sup>2</sup>. If AD and PM are medians of △'s ABC and PQR respectively, and length of PM is 10 cm, then length of AD is 1. cm 2. cm 3. 15 cm 4. 22.5 cm
Related Questions
If ABC and BDE are two equilateral triangles such that D is mid-point of BC, then the ratio of the areas of triangles ABC and BDE is
2 : 1
1 : 2
1 : 4
4 : 1
The areas of two similar triangles are 81 cm2 and 49 cm2 respectively. If an altitude of the smaller triangle is 3.5 cm, then the corresponding altitude of the bigger triangle is
9 cm
7 cm
6 cm
4.5 cm
In the adjoining figure, ∠1 = ∠2 and ∠3 = ∠4. Show that PT × QR = PR × ST.
In the adjoining figure, AB = AC. If PM ⊥ AB and PN ⊥ AP, show that PM × PC = PN × PB.
